如何让程序在执行操作时循环遍历更改列表

Question

假设我有两个包含自然数元素的列表。

Set A 有 n 个元素，Set B 从单个元素开始。

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现在我可以编写一个程序，从 Set A 中获取一个成员，执行一个操作 涉及集合 B 中的所有元素，然后将集合 A 中的元素添加到集合 B。重复此过程直到集合 A 中的所有元素都添加到集合 B。

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示例：

Set A = {3, 4, 5, 6} & Set B = {2}

检查集合 A 中的第一个元素是否可以被集合 B 中的任何元素完全分割。完成此检查后，来自 A 的第一个元素进入集合 B。

Set A = {4, 5, 6} & Set B = {2, 3}

Repeat

Set A = {5, 6} & Set B = { 2, 3, 4 } 

Repeat 

Set A = {6} & Set B = { 2, 3, 4, 5 }

Repeat

Set A = {} & Set B = { 2, 3, 4, 5, 6 }

END

已解决

def getprime(n):

for p in range(2, n+1):
    for i in range(2, p):
        if p % i == 0:
            break
    else:
        print(p)

Answer 1

此代码解决了您的示例问题

检查集合 A 中的第一个元素是否可以被集合 B 中的所有元素完全分割。完成此检查后，来自 A 的第一个元素进入集合 B。

我希望你能理解如何将此应用于其他类似的问题。

A = [2, 4, 5, 6]
B = [2]

# while the list A is not empty
while len(A) > 0:
    # the first number in the list
    num = A[0]
    # for every element in list B
    for j in B:
        fully_divisible = True
        # the the number is not divisible by a number from list B
        if num % j != 0:
            fully_divisible = False

    if fully_divisible:
        # this will only print if ALL the numbers currently in list B are divisible by num
        print num, "can be divided wholly by all elements from set B"
    else:
        # this will print if there is at least one number in list B the is not divisible by num
        print num, "cannot be divided wholly by all elements from set B"

    # remove the first element from list A, next time we loop the first element of the list (A[0]) will be different
    A.remove(num)
    # add that number to list B
    B.append(num)

输出：

2 can be divided wholly by all elements from set B
4 can be divided wholly by all elements from set B
5 cannot be divided wholly by all elements from set B
6 cannot be divided wholly by all elements from set B