【发布时间】:2018-11-22 21:05:09
【问题描述】:
如果有人可以帮助我创建 xslt 以根据重复属性的值从 XML 中删除重复节点,我将不胜感激。在下面的示例中,属性是 PublisherName 和 Data
输入
<RuleCollection>
<FilePublisherRule Id="1">
<Conditions>
<FilePublisherCondition PublisherName="O=Vendor1">
<BinaryVersionRange LowSection="*" HighSection="*" />
</FilePublisherCondition>
</Conditions>
</FilePublisherRule>
<FilePublisherRule Id="2">
<Conditions>
<FilePublisherCondition PublisherName="O=Vendor2">
<BinaryVersionRange LowSection="*" HighSection="*" />
</FilePublisherCondition>
</Conditions>
</FilePublisherRule>
<FilePublisherRule Id="3">
<Conditions>
<FilePublisherCondition PublisherName="O=Vendor1">
<BinaryVersionRange LowSection="*" HighSection="*" />
</FilePublisherCondition>
</Conditions>
</FilePublisherRule>
<FileHashRule Id="10">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xF11BD15D6A565071AED8D3581012C5B5EE0AB46795CEF4ECD712F7572A3DBE36" SourceFileName="_IU14D2N.TMP" SourceFileLength="0" />
<FileHash Type="SHA256" Data="0xF11BD15D6A565071AED8D3581012C5B5EE0AB46795CEF4ECD712F7572A3DBE36" SourceFileName="UNINS000.EXE" SourceFileLength="0" />
<FileHash Type="SHA256" Data="0x5831F348B9B2744F56631CFB2FCAB676BD8B9D3EE407A2DE2C66BC3C395A9E73" SourceFileName="CO.EXE" SourceFileLength="0" />
<FileHash Type="SHA256" Data="0x4BA8285055A9CF8EE146F738DC8526CCD1E509B03984FE1914A6826C7CD530EE" SourceFileName="SETUPCO.EXE" SourceFileLength="0" />
<FileHash Type="SHA256" Data="0x4BA8285055A9CF8EE146F738DC8526CCD1E509B03984FE1914A6826C7CD530EE" SourceFileName="SETUPDAR.EXE" SourceFileLength="0" />
</FileHashCondition>
</Conditions>
</FileHashRule>
<RuleCollection/>
我需要
<RuleCollection>
<FilePublisherRule Id="1">
<Conditions>
<FilePublisherCondition PublisherName="O=Vendor1">
<BinaryVersionRange LowSection="*" HighSection="*" />
</FilePublisherCondition>
</Conditions>
</FilePublisherRule>
<FilePublisherRule Id="2">
<Conditions>
<FilePublisherCondition PublisherName="O=Vendor2">
<BinaryVersionRange LowSection="*" HighSection="*" />
</FilePublisherCondition>
</Conditions>
</FilePublisherRule>
<FileHashRule Id="10">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xF11BD15D6A565071AED8D3581012C5B5EE0AB46795CEF4ECD712F7572A3DBE36" SourceFileName="UNINS000.EXE" SourceFileLength="0" />
<FileHash Type="SHA256" Data="0x5831F348B9B2744F56631CFB2FCAB676BD8B9D3EE407A2DE2C66BC3C395A9E73" SourceFileName="CO.EXE" SourceFileLength="0" />
<FileHash Type="SHA256" Data="0x4BA8285055A9CF8EE146F738DC8526CCD1E509B03984FE1914A6826C7CD530EE" SourceFileName="SETUPCO.EXE" SourceFileLength="0" />
</FileHashCondition>
</Conditions>
</FileHashRule>
<RuleCollection/>
我检查了一些已经存在的案例,似乎我需要在 xslt 中使用一些模板并使用 Munechian 分组,但我没有经验。
我已经使用这个 xslt 删除了重复的 FileHash 节点
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output omit-xml-declaration="no" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="kPropertyByName" match="FileHash" use="@Data"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template
match="FileHash[
not(
generate-id() =
generate-id(key('kPropertyByName', @Data)[1])
)
]"/>
</xsl:stylesheet>
我还有一个比原始文件大的输出文件,为什么?我需要更小。 我想下一步是添加第二个模板来处理基于 PublishedName 值的 FilePublisherRule 节点删除
我添加了第二个模板
<xsl:template
match="FileHash[
not(
generate-id() =
generate-id(key('kPropertyByName', @Data)[1])
)
]"/>
<xsl:template
match="FilePublisherCondition[
not(
generate-id() =
generate-id(key('kProperty1ByName', @PublisherName)[1])
)
复制节点 FilePublisherCondition 删除但父节点离开
<FilePublisherRule Id="0355cba7-7d4a-4a74-9579-8d2192fa0514" Name="Signed by O=ADOBE SYSTEMS INCORPORATED, L=SAN JOSE, S=CALIFORNIA, C=US" Description="" UserOrGroupSid="S-1-1-0" Action="Allow">
<Conditions>
<FilePublisherCondition PublisherName="O=ADOBE SYSTEMS INCORPORATED, L=SAN JOSE, S=CALIFORNIA, C=US" ProductName="*" BinaryName="*">
<BinaryVersionRange LowSection="*" HighSection="*"></BinaryVersionRange>
</FilePublisherCondition>
</Conditions>
</FilePublisherRule>
<FilePublisherRule Id="0355cba7-7d4a-4a74-9579-8d2192fa0514" Name="Signed by O=ADOBE SYSTEMS INCORPORATED, L=SAN JOSE, S=CALIFORNIA, C=US" Description="" UserOrGroupSid="S-1-1-0" Action="Allow">
<Conditions></Conditions>
</FilePublisherRule>
<FilePublisherRule Id="0355cba7-7d4a-4a74-9579-8d2192fa0514" Name="Signed by O=ADOBE SYSTEMS INCORPORATED, L=SAN JOSE, S=CALIFORNIA, C=US" Description="" UserOrGroupSid="S-1-1-0" Action="Allow">
<Conditions></Conditions>
</FilePublisherRule>
<FilePublisherRule Id="e9a23377-81af-41dd-b65d-d8f45c7eac7f" Name="myAgent (O=FLEXERA SOFTWARE LLC, L=SCHAUMBURG, S=ILLINOIS, C=US)" Description="myAgent (6.2.1.172)" UserOrGroupSid="S-1-1-0" Action="Allow">
<Conditions>
<FilePublisherCondition PublisherName="O=FLEXERA SOFTWARE LLC, L=SCHAUMBURG, S=ILLINOIS, C=US" ProductName="*" BinaryName="*">
<BinaryVersionRange LowSection="*" HighSection="*"></BinaryVersionRange>
</FilePublisherCondition>
</Conditions>
</FilePublisherRule>
<FilePublisherRule Id="e9a23377-81af-41dd-b65d-d8f45c7eac7f" Name="myAgent (O=FLEXERA SOFTWARE LLC, L=SCHAUMBURG, S=ILLINOIS, C=US)" Description="myAgent (6.2.1.172)" UserOrGroupSid="S-1-1-0" Action="Allow">
<Conditions></Conditions>
</FilePublisherRule>
<FileHashRule Id="c4232cc1-563b-4fa7-84da-19331af01de4" Name="communication clients" Description="" UserOrGroupSid="S-1-1-0" Action="Allow">
<Conditions>
【问题讨论】:
-
到目前为止你有什么尝试?
-
不清楚要删除哪些元素。
Data属性似乎只存在于FileHash元素上,前两个似乎具有相同的Data值,那么为什么第二个没有在想要的输出中删除?至于PublisherName属性,如果FilePublisherCondition元素上的重复属性值是删除祖先FilePublisherRule的条件,我想知道一个例子是否足以解释规则。一个FilePublisherRule可以有多个FilePublisherCondition后代吗? -
有很多关于删除重复的帖子 - 如果您搜索“分组”,则更多。这些问题在 XSLT 2.0 中比在 1.0 中更容易解决,因此首先要确定您是否已经在使用 XSLT 2.0,或者您是否能够安装 XSLT 2.0 处理器。 (请用“xslt 1.0”或“xslt 2.0”标记 XSLT 问题,以节省大家的精力。)
-
@MichaelKay,不幸的是我没有使用 xslt 语言的经验,我正在使用 MS 进程 microsoft.com/en-us/download/details.aspx?id=21714,我想它是第 2 版
-
@MartinHonnen,我已将我的示例更正为更清晰,FilePublisherRule 只有单个 FilePublisherCondition 后代