在 Python 中访问 Twitter API + GetDirectMessages + Arduino

Question

按照教程，我能够获取和解析我自己帐户的 Twitter 流，并通过串行连接发送此信息以与我的 Arduino 项目进行交互。但是，我需要将消息直接发送给我，而不是我的公共提要。下面是获取公共提要的代码，然后是我尝试获取我的直接消息的代码。

我怎样才能做到这一点？

##Import Libraries

import twitter
import serial
import time

##authenticate yourself with twitter
api = twitter.Api(consumer_key='*************', consumer_secret='**************', access_token_key='************', access_token_secret='*************')

##set to your serial port
ser = serial.Serial('/dev/tty.usbmodem1a21', 19200)

## check serial port
def checkokay():
    ser.flushInput()
    time.sleep(3)
    line=ser.readline()
    time.sleep(3)

    if line == ' ':
            line=ser.readline()
    print 'here'

## Welcome message
print 'Starting Wooden Wave!'

def driptwit():
    status = []
    x = 0

    status = api.GetUserTimeline('wooden_wave') ##grab latest statuses

    checkIt = [s.text for s in status] ##put status in an array

    drip = checkIt[0].split() ##split first tweet into words

    ## check for match and write to serial if match
    if drip[0] == '#high':
        print 'Tweet Recieved, raise block high.'
        ser.write('1')
    elif drip[0] == '#low': ##break if done
        ser.write('0')
        print 'Tweet Recieved, raise block low.'
    elif drip[0] == '#light': ##break if done
        ser.write('2')
        print 'Tweet Recieved, turn on LED.'
    else:
    ser.write('0')
    print 'Awaiting Tweet'

while 1:
driptwit() ## call driptwit function
time.sleep(15) ## sleep for 15 seconds to avoid rate limiting

尝试获取直接消息：

##Import Libraries

import twitter
import serial
import time

##authenticate yourself with twitter
api = twitter.Api(consumer_key='***********', consumer_secret='***********', access_token_key='***********', access_token_secret='***********')

##set to your serial port
ser = serial.Serial('/dev/tty.usbmodem1a21', 19200)

## check serial port
def checkokay():
    ser.flushInput()
    time.sleep(3)
    line=ser.readline()
    time.sleep(3)

    if line == ' ':
            line=ser.readline()
    print 'here'

## Welcome message
print 'Starting Wooden Wave!'

def driptwit():
status = []
x = 0

status = api.GetDirectMessages() ##grab latest statuses

checkIt = [s.text for s in status] ##put status in an array

drip = checkIt[0].split() ##split first tweet into words

## check for match and write to serial if match
if drip[0] == '#high':
    print 'Tweet Recieved, raise block high.'
    ser.write('1')
elif drip[0] == '#low': ##break if done
    ser.write('0')
    print 'Tweet Recieved, raise block low.'
elif drip[0] == '#light': ##break if done
    ser.write('2')
    print 'Tweet Recieved, turn on LED.'
else:
    ser.write('0')
    print 'Awaiting Tweet'

while 1:
    driptwit() ## call driptwit function
    time.sleep(15) ## sleep for 15 seconds to avoid rate limiting

//// 更新 //

def driptwit():
    status = []
    x = 0

    status = api.GetMentions() ##grab latest statuses
    print [s.text for s in status]
    checkIt = [s.text for s in status] ##put status in an array

    drip = checkIt[0].split() ##split first tweet into words

    ## check for match and write to serial if match
    if drip[0] == '#high':
        print 'Tweet Recieved, raise block high.'
        ser.write('1')
    elif drip[0] == '#low': ##break if done
        ser.write('0')
        print 'Tweet Recieved, raise block low.'
    elif drip[0] == '#light': ##break if done
        ser.write('2')
        print 'Tweet Recieved, turn on LED.'
    else:
        ser.write('0')
        print 'Awaiting Tweet'

while 1:
    driptwit() ## call driptwit function
    time.sleep(15) ## sleep for 15 seconds to avoid rate limiting

Answer 1

从您的评论看来，api.GetDirectMessages() 返回了一个空列表。在 API 调用之后直接打印 len(status) 以验证这一点。您确定有新的直接消息可供阅读吗？您是否尝试过使用since 参数为api.GetDirectMessages() 设置特定日期？

不要只检查第一个标记中的哈希标记，而是检查整个字符串。换句话说，测试if '#high' in drip 而不是if drip[0] == '#high'。