连接到 Amazon RDS 后 Mysql 创建表时出错

Question

我可以正常连接到 RDS，但是当我尝试使用以下脚本创建表时出现错误。

<?php

define('DB_SERVER', 'rdsdari.MYRDSNAME.rds.amazonaws.com');
define('DB_USERNAME', 'Rds1');
define('DB_PASSWORD', 'Rds1');
define('DB_DATABASE', 'Rds1');

  /* Connect to MySQL and select the database. */
  $connection = mysqli_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD);

  if (mysqli_connect_errno()) echo "Failed to connect to MySQL: " . mysqli_connect_error();

  $database = mysqli_select_db($connection, DB_DATABASE);

  /* Ensure that the Employees table exists. */
  VerifyEmployeesTable($connection, DB_DATABASE);

  /* If input fields are populated, add a row to the Employees table. */
  $employee_name = htmlentities($_POST['Name']);
  $employee_address = htmlentities($_POST['Address']);

  if (strlen($employee_name) || strlen($employee_address)) {
    AddEmployee($connection, $employee_name, $employee_address);
  }
?>

<!-- Input form -->
<form action="<?PHP echo $_SERVER['SCRIPT_NAME'] ?>" method="POST">
  <table border="0">
    <tr>
      <td>Name</td>
      <td>Address</td>
    </tr>
    <tr>
      <td>
        <input type="text" name="Name" maxlength="45" size="30" />
      </td>
      <td>
        <input type="text" name="Address" maxlength="90" size="60" />
      </td>
      <td>
        <input type="submit" value="Add Data" />
      </td>
    </tr>
  </table>
</form>

<!-- Display table data. -->
<table border="1" cellpadding="2" cellspacing="2">
  <tr>
    <td>ID</td>
    <td>Name</td>
    <td>Address</td>
  </tr>

<?php

$result = mysqli_query($connection, "SELECT * FROM Employees");

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}
?>

</table>

<!-- Clean up. -->
<?php

  mysqli_free_result($result);
  mysqli_close($connection);

?>

</body>
</html>


<?php

/* Add an employee to the table. */
function AddEmployee($connection, $name, $address) {
   $n = mysqli_real_escape_string($connection, $name);
   $a = mysqli_real_escape_string($connection, $address);

   $query = "INSERT INTO `Employees` (`Name`, `Address`) VALUES ('$n', '$a');";

   if(!mysqli_query($connection, $query)) echo("<p>Error adding employee data.</p>");
}

/* Check whether the table exists and, if not, create it. */
function VerifyEmployeesTable($connection, $dbName) {
  if(!TableExists("Employees", $connection, $dbName))
  {
     $query = "CREATE TABLE `Employees` (
         `ID` int(11) NOT NULL AUTO_INCREMENT,
         `Name` varchar(45) DEFAULT NULL,
         `Address` varchar(90) DEFAULT NULL,
         PRIMARY KEY (`ID`),
         UNIQUE KEY `ID_UNIQUE` (`ID`)
       ) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1";

     if(!mysqli_query($connection, $query)) echo("<p>Error creating table.</p>");
  }
}

/* Check for the existence of a table. */
function TableExists($tableName, $connection, $dbName) {
  $t = mysqli_real_escape_string($connection, $tableName);
  $d = mysqli_real_escape_string($connection, $dbName);

  $checktable = mysqli_query($connection,
      "SELECT TABLE_NAME FROM information_schema.TABLES WHERE TABLE_NAME = '$t' AND TABLE_SCHEMA = '$d'");

  if(mysqli_num_rows($checktable) > 0) return true;

  return false;
}
?>

现在我明白了

创建表时出错。

添加员工数据时出错。

Answer 1

首先你可能想复制https://docs.aws.amazon.com/AmazonRDS/latest/UserGuide/CHAP_Tutorials.WebServerDB.CreateWebServer.html上的启动代码

这与您的代码相同。

如果您仍然遇到错误，您可以将这两个语句 echo("<p>Error creating table.</p>") 和 echo("<p>Error adding employee data.</p>") 替换为 echo("Error description: " . mysqli_error($connection)); 以获取详细的错误代码消息