postgres获取两列引用相同父ID的数据答案

【问题标题】：postgres getting data where two column references same parent idpostgres获取两列引用相同父ID的数据
【发布时间】：2011-08-09 06:49:57
【问题描述】：

postgres 数据库中有 3 个表

CREATE TABLE tab_name
(
  name_id integer NOT NULL,
  cust_name character varying NOT NULL, -- contains names like david,jones,athur
  CONSTRAINT tab_name_pkey PRIMARY KEY (name_id)
)

CREATE TABLE tab_rel
(
  rel_id integer NOT NULL,
  rel_desc character varying NOT NULL,-- contains relation description father son, sister brother
  CONSTRAINT tab_rel_pkey PRIMARY KEY (rel_id)
)

CREATE TABLE tab_rel_map
(
  rel_id integer NOT NULL,
  name_id1 integer NOT NULL,
  name_id2 integer NOT NULL,
  CONSTRAINT tab_rel_map_name_id1_fkey FOREIGN KEY (name_id1)
      REFERENCES tab_name (name_id) MATCH SIMPLE
      ON UPDATE NO ACTION ON DELETE NO ACTION,
  CONSTRAINT tab_rel_map_name_id2_fkey FOREIGN KEY (name_id2)
      REFERENCES tab_name (name_id) MATCH SIMPLE
      ON UPDATE NO ACTION ON DELETE NO ACTION,
  CONSTRAINT tab_rel_map_rel_id_fkey FOREIGN KEY (rel_id)
      REFERENCES tab_rel (rel_id) MATCH SIMPLE
      ON UPDATE NO ACTION ON DELETE NO ACTION
)

我正在尝试编写以 rel_id 作为输入的函数，并且应该根据 name_id1 和 name_id2 输出 cust_name。因为 name_id1 和 name_id2 都引用了相同的父 ID，所以我无法获得各自的名称。

rel_id | relation     | cust_name1 | cust_name2
------------------------------------------------
1      | Father son   | David      | Jones

【问题讨论】：

标签： postgresql foreign-keys reference primary-key

【解决方案1】：

您需要加入同一张表两次 - 以下是使用 aliases 的方法：

select 
    rm.rel_id,
    r.rel_desc as relation,
    n1.cust_name as cust_name1,
    n2.cust_name as cust_name2
from tab_rel_map rm
join tab_rel r on r.id = rm.rel_id
left join tab_name n1 on n1.name_id = rm.name_id1
left join tab_name n2 on n2.name_id = rm.name_id2
where rm.rel_id = 1;

【讨论】：