在子查询中使用 min() 和 avg()

Question

我正在使用 ibm cloud 和 sql 开发 db2。 我的数据包含 1 个包含 3 列的表：学校、它们的整体表现（水平）和位置。 我想使用带有 avg 和 min 的子查询来找到 AVERAGE 级别最低的位置。

我有这段代码可以完成这项工作：

select location, avg(level) as avglevel
from schools_table
group by location
order by avglvl
limit 1;

但我正在寻找类似的东西：

select location
from schools_table
where level = (select min(level) from schools_table);

这会产生所有值中的最小值。但是我对平均值的最小值感兴趣。

请帮忙 非常感谢您的任何见解。

阿图罗

Answer 1

你可以试试下面的-

with cte as
(
select location,avg(safety_score) as safety_score  from chicago_public_schools group by location
)
select community_area_name
from chicago_public_schools
where safety_score = (select min(safety_score) from cte)

Answer 2

我认为你只需要

select community_area_name
from chicago_public_schools
where safety_score = (select avg(safety_score)
                      from chicago_public_schools 
                      group by location
                      order by avg(safety_score) asc --sort the result
                      limit 1); --pick the smallest avg

现在..出于性能原因，我不建议这样做，但如果您真的想避免使用 order by 和 limit 并且不想使用 cte，您可以使用 @ 987654325@

select community_area_name
from chicago_public_schools
where safety_score = (select distinct min(avg(safety_score)) over()
                      from chicago_public_schools 
                      group by location)

如果你也想避免window functions，你可以完全依赖子查询，但是——它太丑了

select community_area_name
from chicago_public_schools a
join (select min(safety_score) as min_safety_score
      from (select avg(safety_score) as safety_score  
            from chicago_public_schools 
            group by location) b) c on a.safety_score = c.min_safety_score