如何根据条件对列名进行排序？

Question

我有一个包含以下列的表格-

• 事件 ID (varchar)
• 创建日期（varchar- eg- '01-OCT-2014'）
• 状态（varchar- eg- 'open','closed'）

我需要根据状态和从创建日期开始的日期范围来统计事件。

例如。

Date Range       || Open          || Closed ||
1-2 days         ||         5     ||       6 ||
2-5 days         ||         4     ||       8 ||
5-15 days        ||         10    ||       15 ||

任何帮助将不胜感激，谢谢。

Answer 1

SELECT CASE WHEN DATEDIFF(created_date, now()) BETWEEN 1 AND 2
                THEN '1-2 days'
            WHEN DATEDIFF(created_date, now()) BETWEEN 3 AND 5
                THEN '3-5 days'
            WHEN DATEDIFF(created_date, now()) BETWEEN 6 AND 15
                THEN '6-15 days'
            ELSE '> 15 days'
        END AS DateRange,
        SUM(CASE WHEN Status = 'open' THEN 1 ELSE 0 END) AS Open,
        SUM(CASE WHEN Status = 'closed' THEN 1 ELSE 0 END) AS Closed
FROM YourTable
GROUP BY DateRange