Angular 2 路由无法正常工作答案

【问题标题】：Angular 2 routing not working properlyAngular 2 路由无法正常工作
【发布时间】：2016-09-04 02:18:11
【问题描述】：

我似乎无法让路由在 Angular 2 中与子级一起使用。该应用程序是我的第一个 Angular 2 应用程序，它非常简单，顶部有一个导航栏，应该在底部填充内容页。每当我点击任何导航链接时，它们都会导航到同一个孩子，甚至更糟糕的是那个孩子堆栈的内容，这意味着我点击一次，孩子在下面加载，我再次点击它再次在下面加载，所以我有两次，以此类推。

完整的内容可以在这里找到：plunker

这是我的 searchs.routing.ts 文件：

import { ModuleWithProviders } from '@angular/core';
import { Routes, RouterModule } from '@angular/router';

import { AdvancedSearchComponent } from './advanced-search/advanced-search.component';
import { GuidedSearchComponent } from './guided-search/guided-search.component';
import { QuickSearchComponent } from './quick-search/quick-search.component';

const searchesRoutes: Routes = [
    {
        children: [
            { path: 'advanced-search', component: AdvancedSearchComponent },
            { path: 'guided-search', component: GuidedSearchComponent },
            { path: 'quick-search', component: QuickSearchComponent }
        ],
        path: '',
        component: GuidedSearchComponent
    }
];

export const searchesRouting: ModuleWithProviders = RouterModule.forChild(searchesRoutes);

这是我的 app.routing.ts 文件：

import { ModuleWithProviders } from '@angular/core';
import { Routes, RouterModule } from '@angular/router';

const searchesRoutes: Routes = [
    { path: 'searches', loadChildren: 'app/searches/searches.module#SearchesModule' },
    { path: '', redirectTo: "/searches", pathMatch: 'full' }
];

const appRoutes: Routes = [
    ...searchesRoutes
];

export const appRoutingProviders: any[] = [
];

export const routing: ModuleWithProviders = RouterModule.forRoot(appRoutes);

同样，这不能正常工作，但如果我像这样在主文件中执行所有路由：

import { ModuleWithProviders } from '@angular/core';
import { Routes, RouterModule } from '@angular/router';

import { AdvancedSearchComponent } from './searches/advanced-search/advanced-search.component';
import { GuidedSearchComponent } from './searches/guided-search/guided-search.component';
import { QuickSearchComponent } from './searches/quick-search/quick-search.component';

const appRoutes: Routes = [
    { path: 'searches/advanced-search', component: AdvancedSearchComponent },
    { path: 'searches/guided-search', component: GuidedSearchComponent },
    { path: 'searches/quick-search', component: QuickSearchComponent },
    { path: '', redirectTo: "/searches/guided-search", pathMatch: 'full' }
];

export const appRoutingProviders: any[] = [
];

export const routing: ModuleWithProviders = RouterModule.forRoot(appRoutes);

但我想学习如何将搜索路由委托给子模块以使其更易于管理。

【问题讨论】：

标签： angular angular2-routing

【解决方案1】：

您应该在 searchesRoutes 中为您的子路由添加根组件，例如：

@Component({
    selector: 'art-search',
    template: `<router-outlet></router-outlet>`
})
export class SearchComponent {}

您还必须指定默认路由，例如：

{ path: '', redirectTo: '/guided-search', pathMatch: 'full' }

那么您的 searches.routing.ts 文件将是：

const searchesRoutes: Routes = [
  {
    children: [
      { path: 'advanced-search', component: AdvancedSearchComponent },
      { path: 'guided-search', component: GuidedSearchComponent },
      { path: 'quick-search', component: QuickSearchComponent },
      { path: '', redirectTo: '/guided-search', pathMatch: 'full' }
    ],
    path: '', component: SearchComponent
  } 
];

在此处查看更多详细信息Plunker

【讨论】：