Laravel Eloquent 查询修改

Question

在我的应用程序中，我有三个表：问题、类别和主题。当我添加问题时，我选择了一个类别，它会添加类别名称和主题名称。

我试过这种方式；它有效，但我认为这不是最好的方法。

public function store() 
{
    $category = Input::get('category');

    $categoryName = DB::table('category')
            ->where('categoryId', 'LIKE', $category)
            ->pluck('categoryName');

    $themeId = DB::table('category')
            ->where('categoryId', 'LIKE', $category)
            ->pluck('themeId');

    $themeName = DB::table('theme')
            ->where('themeId', 'LIKE', $themeId)
            ->pluck('themeName');


    $question = new questionList;

    $question->questionId = Input::get('questionId');
    $question->question = Input::get('question');
    $question->rightAnswer = Input::get('rightAnswer');
    $question->explanation = Input::get('explanation');
    $question->wrongAnswer1 = Input::get('wrongAnswer1');
    $question->wrongAnswer2 = Input::get('wrongAnswer2');
    $question->wrongAnswer3 = Input::get('wrongAnswer3');
    $question->theme = $themeName;
    $question->category = $categoryName;
    $question->difficulty = Input::get('difficulty');

    $question->save();

    if ($question->save()) 
    {
        return Response::json(array(
                'status' => 'ok',
                'message' => 'success',
        ));
    }
}

Answer 1

就这么简单：

$category = DB::table('category')
 ->where('categoryId','LIKE',$category)
 ->first();

$categoryName = $category->name;
$themeId      = $category->themeId;
$themeName    = $category->themeName;