查找数据集中出现频率最高的单词

Question

我编写了一个函数，它接受一个列表作为输入并返回列表中最常见的项目。

##Write the function
def most_frequent(List): 
    dict = {} 
    count, itm = 0, '' 
    for item in reversed(List): 
        dict[item] = dict.get(item, 0) + 1
        if dict[item] >= count : 
            count, itm = dict[item], item 
    return(item) 
  
    return num 

# verfiy the code 

list = [5,42,34,6,7,4,2,5]
print(most_frequent(list)) 

然后下载两个文本文件以获取最常用的单词。

# Download the files restaurants.txt and restaurant-names.txt from Github
!curl https://raw.githubusercontent.com/ipeirotis/introduction-to-python/master/data/restaurant-names.txt -o restaurant-names.txt
!curl https://raw.githubusercontent.com/ipeirotis/introduction-to-python/master/data/restaurants.txt -o restaurants.txt



# create the list from the restaurants.txt
  List = open("restaurants.txt").readlines()

# get the most most frequent restaurant names
print("The most frequent restaurant names is ",most_frequent(List))

print(most_common(List))

但是当我尝试查找出现在餐厅名称中的最常用词时。我得到了同样的结果。你能帮忙检查一下这是否正确吗？谢谢

 # create the list from the restaurants.txt
List = open("restaurants.txt").readlines()

# get the most most frequent restaurant names
print("The most frequent restaurant names is ",most_frequent(List))

Answer 1

它是return itm（最常见的项目）而不是return item（反向列表的最后一部分）

Answer 2

您似乎为餐厅名称文件使用了错误的文件名。从你的 curl 命令来看：

!curl https://raw.githubusercontent.com/ipeirotis/introduction-to-python/master/data/restaurant-names.txt -o restaurant-names.txt

您应该使用的文件名是restaurant-names.txt，因此您的代码应该是：

 # create the list from the restaurants.txt
List = open("restaurants-names.txt").readlines()

# get the most most frequent restaurant names
print("The most frequent restaurant names is ",most_frequent(List))

Answer 3

可能是函数出错了，如果你尝试相同的测试数据但顺序不同，例如：list = [42,5,34,6,5,7,4,2]而不是list = [5,42,34,6,7,4,2,5]，输出仍然是5吗？