Python3 避免在 csv 文件末尾引用和额外的行

Question

我正在尝试根据之前创建和连接的列表内容创建 CSV 文件。交易是我所有的行记录在每行的开头和结尾都带有双引号。此外，在文件末尾，我得到了一条额外的白线。

代码：

with open('/tmp/'+filename,"w", newline='') as output:
            writer = csv.writer(output)
            for item in update_records:
                row = '{},{},{}'.format(item['field1'],item['field2'],item['field3'])
                #print(row)
                writer.writerow([row])               

        output.close()

当前输出：

我试过了：

writer = csv.writer(output, quotechar='', quoting=csv.QUOTE_MINIMAL)

但我收到如下错误：

如果启用引用，则必须设置quotechar

非常感谢您的支持。

Answer 1

这里是一个使用 DictWriter 的答案，但是基于数据结构的大量猜测。还有更简单的方法来编写它，例如您将它们作为字典列表。

import csv

update_records = [
    {
        "field1": "field1",
        "field2": "en",
        "field3": "field3"
    },
    {
        "field1": "field1",
        "field2": "de",
        "field3": "field3"
    }
]

filename = "test.csv"

with open('/tmp/'+filename,"w", newline='') as output:
    # Define header, needed even if not written when using DictWriter
    header = ["field1", "field2", "field3"]
    writer = csv.DictWriter(output, fieldnames=header)
    # Optional write the header
    # writer.writeheader()
    for item in update_records:
        row = {}
        # Only provide the fields 1 to 1 that are present in the header.
        # There are plenty of cooler ways to do this, but hope this is clearer.
        for head in header:
            row[head] = item[head]
        # print(row)
        writer.writerow(row)

输出是这样的（/tmp/test.csv）（末尾有一个空行，但是不知道如何将其显示为代码的一部分，因此添加了 EOF）：

field1,en,field3
field1,de,field3

EOF

Answer 2

writerow 应该将字段列表作为参数：

with open('/tmp/'+filename,"w", newline='') as output:
    writer = csv.writer(output)
    for item in update_records:
        row = [item['field1'],item['field2'],item['field3']]
        #print(row)
        writer.writerow(row)