Terragrunt 依赖列表输出作为输入答案

【问题标题】：Terragrunt dependency list output as inputsTerragrunt 依赖列表输出作为输入
【发布时间】：2020-11-06 12:19:52
【问题描述】：

我有两个入口点：s3 和 do_something。 s3 是 do_something 的依赖项，代码如下：

terragrunt.hcl

aws_regions = [ "us-east-1", "eu-east-1" ]
inputs = {
  build_bucket = {
    "${local.aws_regions[0]}" = {
      name = "somename-${local.aws_regions[0]}"
    }
    "${local.aws_regions[1]}" = {
      name = "somename-${local.aws_regions[1]}"
    }
  }
}

main.tf

resource "aws_s3_bucket" "build_bucket" {
  for_each = var.build_bucket
  bucket = each.value["name"]
  acl    = "private"
}
output "build_bucket" {
  value = aws_s3_bucket.build_bucket[*]
}

--terragrunt-debug 看起来像：

  "build_bucket": [
    [
      {
        "eu-east-1": {
          "acceleration_status": "",
          "acl": "private",
          "arn": "arn:aws:s3:::somename-eu-east-1",
          "bucket": "somename-eu-east-1",
        },
        "us-east-1": {
          "acceleration_status": "",
          "acl": "private",
          "arn": "arn:aws:s3:::somename-us-east-1",
          "bucket": "somename-us-east-1",
        }
      }
    ]
  ],

在 do_something 文件夹中，我有 terragrunt.hcl：

dependency "s3" {
  config_path = "../s3"
}
inputs = {
  build_bucket = [dependency.s3-build.outputs.build_bucket]
}

vars.tf

variable "build_bucket" {
  description = "S3 buckets"
  type = list
}

如何获取 build_bucket 的每个元素？

这没有用：

var.build_bucket[0].[data.aws_region.current.name].bucket

【问题讨论】：

标签： terragrunt

【解决方案1】：

嵌套列表... 变量设置为 any 而不是字符串。

variable "build_bucket_arn" {
  description = "S3 bucket ARN for the builds"
  type = any

调用原始嵌套列表：

var.build_bucket[0][0][data.aws_region.current.name].bucket

【讨论】：