【发布时间】:2019-05-20 12:11:18
【问题描述】:
当我尝试评估类别模型中的数据时,我在 Laravel 中收到“尝试获取非对象的属性 'display_name'”错误。
我有 2 个模型:帖子和类别;我有相应的表格:Posts('id', 'title', 'body', 'cover_image')
和Categories('id', 'display_name','name', 'key).
数据透视表是:category_post
这是我的帖子模型:
namespace App;
use Illuminate\Database\Eloquent\Model;
class Post extends Model
{
//Table Name
protected $table = 'posts';
//Model Relationships
public function tag(){
return $this->belongsToMany('App\Tag', 'id');
}
public function category() {
return $this->belongsTo('App\Category','id');
}
}
这是我的类别模型:
namespace App;
use Illuminate\Database\Eloquent\Model;
class Category extends Model
{
protected $table = 'categories';
//Model Relationships
public function post()
{
return $this->belongsTo('App\Post', 'id');
}
}
另外,这是我的 PagesController:
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Post;
class PagesController extends Controller
{
public function index()
{
if ( !is_null(Post::class) ) {
$posts = Post::latest()->with('category')->paginate(5);
return view('pages.index')->with(['posts' => $posts]);
}
else {
return view('pages.empty');
}
}
这是我的刀片文件:
@if(count($posts) > 0)
@foreach($posts as $post)
<span> <i class="fa fa-folder-open"></i> {{ $post->category->display_name }} </span>
@endforeach
@endif
更新
这些是我的迁移: 帖子表:
use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;
class CreatePostsTable extends Migration
{
/**
* Run the migrations.
*
* @return void
*/
public function up()
{
Schema::create('posts', function (Blueprint $table) {
$table->increments('id');
$table->string('title');
$table->string('slug')->nullable();
$table->mediumText('body');
$table->string('cover_image')->default('noimage.jpg')->nullable();
$table->integer('user_id');
$table->timestamps();
$table->integer('category_id')->unsigned()->nullable();
$table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');
$table->foreign('category_id')->references('id')->on('categories')->onDelete('cascade');
});
}
/**
* Reverse the migrations.
*
* @return void
*/
public function down()
{
Schema::dropIfExists('posts');
}
}
还有我的分类表:
use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;
class CreateCategoriesTable extends Migration
{
/**
* Run the migrations.
*
* @return void
*/
public function up()
{
Schema::create('categories', function (Blueprint $table) {
$table->increments('id');
$table->string('name')->unique();
$table->string('display_name');
$table->string('description')->nullable();
$table->string('password')->nullable();
$table->timestamps();
});
}
/**
* Reverse the migrations.
*
* @return void
*/
public function down()
{
Schema::dropIfExists('categories');
}
}
预期的结果是从类别表中获取 display_name 并以列表方式显示它们。 这是我不断收到的错误
试图获取非对象的属性“display_name”(视图:D:\xampp\htdocs\MyProject\resources\views\pages\index.blade.php)
我试过这样称呼它:
<span> <i class="fa fa-folder-open"></i> {{ $post->category()->display_name }} </span>
但它也不起作用。
编辑:
在Controller中转储$post变量后:
Post {#331 ▼
#table: "posts"
#fillable: array:7 [▼
0 => "id"
1 => "title"
2 => "slug"
3 => "body"
4 => "cover_image"
5 => "user_id"
6 => "category_id"
]
+primaryKey: "id"
+timestamps: true
#connection: "mysql"
#keyType: "int"
+incrementing: true
#with: []
#withCount: []
#perPage: 15
+exists: true
+wasRecentlyCreated: false
#attributes: array:9 [▼
"id" => 1
"title" => "This is a Base Announcement"
"slug" => null
"body" => "Please feel free to delete this announcement and create a new one afterwards."
"cover_image" => "noimage.jpg"
"user_id" => 1
"created_at" => "2019-05-20 14:22:45"
"updated_at" => "2019-05-20 14:22:45"
"category_id" => null
]
#original: array:9 [▼
"id" => 1
"title" => "This is a Base Announcement"
"slug" => null
"body" => "Please feel free to delete this announcement and create a new one afterwards."
"cover_image" => "noimage.jpg"
"user_id" => 1
"created_at" => "2019-05-20 14:22:45"
"updated_at" => "2019-05-20 14:22:45"
"category_id" => null
]
#changes: []
#casts: []
#dates: []
#dateFormat: null
#appends: []
#dispatchesEvents: []
#observables: []
#relations: []
#touches: []
#hidden: []
#visible: []
#guarded: array:1 [▼
0 => "*"
]
}
【问题讨论】:
-
您必须在模型和表“posts”上插入外键“category_id”
-
$post->category->pivot->display_name? -
@Diego Ive 已将外键添加到表中;但是如何将它添加到模型中?
-
@quickSwap 我没听懂。
标签: php eloquent laravel-5.8