【发布时间】:2016-10-04 16:37:33
【问题描述】:
我正在学习laravel 4.2,对构造函数查询雄辩有疑问,我有以下代码
public static function filterInvoicingReport($valuesFilter){
$fechaInicio='';
$fechaFin='';
$customerId='';
$state='';
if($valuesFilter == null)
return;
//obtenemos los valores de las variables dateRegisterStart y dateRegisterEnd
if(array_key_exists('fechaInicio', $valuesFilter)&&array_key_exists('fechaFin', $valuesFilter)){
$fechaInicio=$valuesFilter['fechaInicio'];
$fechaFin=$valuesFilter['fechaFin'];
}
if(array_key_exists('customerId',$valuesFilter)){
$customerId=$valuesFilter['customerId'];
}
if(array_key_exists('state',$valuesFilter)){
$state=$valuesFilter['state'];
}
$sql= DB::table('invoice')
-> select(
'invoice.id_invoice',
'invoice.invoice_number',
'invoice.created_date',
'invoice.name_seller',
'invoice.conditions',
'invoice.total_sale',
'invoice.status',
'invoice.customerId',
'customer.name as customerName',
'customer.identificationId as customerDNI')
-> whereBetween(DB::raw('DATE_FORMAT(invoice.created_date,"%Y-%m-%d")'),[$fechaInicio,$fechaFin])
->Where('invoice.status','=',$state)
->Where('invoice.customerId','=',$customerId)
-> join('customer','customer.customerId','=','invoice.customerId');
-> get();
return $sql;
}
是查询报表,问题是$state和$customerId可以为空,查询返回全部为空。
我想要的是,如果 php 中的变量为空,则只返回 ->where 有一个不为空的变量。
【问题讨论】: