如何在 Laravel 中的 unionAll 之后将 group by 添加到 eloquent 查询？答案

【问题标题】：How to add group by to eloquent query after unionAll in Laravel?如何在 Laravel 中的 unionAll 之后将 group by 添加到 eloquent 查询？
【发布时间】：2020-02-17 08:54:13
【问题描述】：

我想把这个 Mysql 代码转换成 Laravel Eloquent

select service_id, sum(cnt) from 
(
    select * from 
    (
        select service_id, count(*) cnt from prdouct_notifs 
        join products on products.id = prdouct_notifs.product_id 
        where prdouct_notifs.user_id = 268 
        and prdouct_notifs.deleted_at is null 
        and prdouct_notifs.block = 4 
        group by service_id
    ) first_table 

   union All
   (
       select service_id, count(*) cnt from products
       where products.pro_user_id = 268
       and products.status = 47575 
       group by service_id
  )
) total_union group by service_id

我将此代码更改为 Laravel Eloquent。

$get_product = Product::where('pro_user_id', 268)
    ->where('status', 47575)
    ->groupby('service_id')
    ->selectRaw('service_id ,count(*) cnt');

$get_final_product = prdouct_notifs::join('products', function ($join){
    $join->on('products.id', '=', 'prdouct_notifs.product_id')
        ->where('prdouct_notifs.user_id', 268)
        ->where('prdouct_notifs.block', 4);
})
    ->selectRaw('service_id ,count(*) cnt')
    ->groupby('service_id')
    ->unionAll($get_product)
    ->get();

问题是unionAll之后如何运行groupby

这就是我想改成雄辩的。

total_union group by service_id

【问题讨论】：

您真的需要在子查询中按 service_id 分组吗？只要你有所有的结果，你以后肯定可以分组和计数
您可以在检索到集合后对其进行分组。 laravel.com/docs/6.x/collections#method-groupby

标签： php mysql laravel laravel-5 eloquent

【解决方案1】：

我的想法是在分组之前将 UNION 放入子查询中。我希望这能回答您的问题。

$product = DB::table('products as p')
    ->where('p.status', 47575)
    ->select('p.service_id as service_id');

$productNotify= DB::table('prdouct_notifs as pn')
    ->select('pn.service_id as service_id')
    ->union($product);

$groupby = DB::query()->fromSub($productNotify, 'p_pn')
    ->select('service_id', DB::raw('COUNT(*) as cnt'))
    ->groupBy('service_id');

产生以下 SQL

select "stud_id", COUNT(*) as total_asset from (
   select * from (select p.service_id as service_id from products as p) 
   union 
   select * from (select pn.service_id as service_id from prdouct_notifs as pn) 
) as p_pn 
group by service_id

【讨论】：