【发布时间】:2018-06-26 04:29:25
【问题描述】:
我有一条路径,用户输入 player_id 是 PlayerWife 表中的外键:
Route::get('player/wife/{player_id}','WifeController@showWife');
然后在 WifeController 里面我放的 showWife 函数:
public function showWife($player_id)
{
$playerWife = PlayerWife::where('player_id',$player_id);
return $playerWife;
}
但是它会抛出一个错误:
Object of class Illuminate\Database\Eloquent\Builder could not be converted to string
通过 player_id 和 eloquent 选择 PlayerWife 的正确方法是什么?
【问题讨论】:
标签: laravel eloquent foreign-keys