从三个表的子查询中选择 MAX 值答案

【问题标题】：Selecting the MAX value from a subquery of three tables从三个表的子查询中选择 MAX 值
【发布时间】：2014-05-07 19:10:18
【问题描述】：

我正在尝试从下面的查询中选择 LAST_MDS_MON 为 MAX 的 SECTION,LAST_MDS_MON,DAYS_BETWEEN 以用于不同的 SECTION...请帮助！

SELECT STATE_CODE||SHRP_ID AS SECTION,MAX(SURVEY_DATE) AS LAST_MDS_MON,((ADD_MONTHS(CURRENT_DATE,18))-TO_DATE(MAX(SURVEY_DATE))) AS DAYS_BETWEEN
FROM MON_DIS_AC_REV
GROUP BY STATE_CODE,SHRP_ID
UNION ALL
SELECT STATE_CODE||SHRP_ID AS SECTION,MAX(SURVEY_DATE) AS LAST_MDS_MON,((ADD_MONTHS(CURRENT_DATE,18))-TO_DATE(MAX(SURVEY_DATE))) AS DAYS_BETWEEN
FROM MON_DIS_JPCC_REV
GROUP BY STATE_CODE,SHRP_ID
UNION ALL
SELECT STATE_CODE||SHRP_ID AS SECTION,MAX(SURVEY_DATE) AS LAST_MDS_MON,((ADD_MONTHS(CURRENT_DATE,18))-TO_DATE(MAX(SURVEY_DATE))) AS DAYS_BETWEEN
FROM MON_DIS_CRCP_REV
GROUP BY STATE_CODE,SHRP_ID

【问题讨论】：

标签： sql oracle subquery max union-all

【解决方案1】：

SELECT
  SECTION,
  LAST_MDS_MON,
  DAYS_BETWEEN
FROM
  (
  SELECT
    SECTION,
    LAST_MDS_MON,
    DAYS_BETWEEN,
    RANK() OVER (PARTITION BY SECTION ORDER BY LAST_MDS_MON desc) AS RANK
  FROM
    (
    SELECT STATE_CODE||SHRP_ID AS SECTION,MAX(SURVEY_DATE) AS LAST_MDS_MON,((ADD_MONTHS(CURRENT_DATE,18))-TO_DATE(MAX(SURVEY_DATE))) AS DAYS_BETWEEN
    FROM MON_DIS_AC_REV
    GROUP BY STATE_CODE,SHRP_ID
    UNION ALL
    SELECT STATE_CODE||SHRP_ID AS SECTION,MAX(SURVEY_DATE) AS LAST_MDS_MON,((ADD_MONTHS(CURRENT_DATE,18))-TO_DATE(MAX(SURVEY_DATE))) AS DAYS_BETWEEN
    FROM MON_DIS_JPCC_REV
    GROUP BY STATE_CODE,SHRP_ID
    UNION ALL
    SELECT STATE_CODE||SHRP_ID AS SECTION,MAX(SURVEY_DATE) AS LAST_MDS_MON,((ADD_MONTHS(CURRENT_DATE,18))-TO_DATE(MAX(SURVEY_DATE))) AS DAYS_BETWEEN
    FROM MON_DIS_CRCP_REV
    GROUP BY STATE_CODE,SHRP_ID
    )
  )
WHERE
  RANK = 1

【讨论】：