【发布时间】:2019-09-08 19:25:50
【问题描述】:
我有两张桌子,比如 1:-用户
id name
1 vivek
2 raj
3 mohan
4 gagan
5 priya
2:-购买
id typee user_id
1 class 1
2 class 1
3 course 1
4 class 2
5 test_series 3
6 test_series 2
我正在尝试运行
select p.id,(select count(purchasee.user_id) as tot
from purchasee
where purchasee.user_id=p.id
and typee='class'
or typee='course' ) as classcourse,(select count(purchasee.user_id) as tot
from purchasee
where purchasee.user_id=p.id
and typee='test_series') as test
from purchasee as p
GROUP by p.user_id
查询及其刺激我
id Classcourse test
1 3 0
4 1 0
5 0 1
预期的答案是
id Classcourse test
1 3 0
4 1 1
5 0 1
我想选择用户购买(课程或课程)或(test_series),如果是,则用户购买课程或课程,然后计算它,或者如果用户购买 test_series,然后计算行数
【问题讨论】:
-
你能解释一下我们的逻辑吗?