【发布时间】:2018-02-24 19:46:42
【问题描述】:
我是 gtest/gmock 的新手,并试图在 c++ 中测试一个简单的函数,它有两个指针“m_propBsh_p”和“m_eBsh_p”;这些指针在一些工厂创建后变得有效,但是我不想参与工厂类的复杂性和回调。 以下是我要为其编写测试的函数定义:
std::string Foo::toString(const std::string &indent) const
{
....
std::string str =
(m_propBsh_p != nullptr) ? m_propBsh_p -> toString("P-BSH: ") : "-";
str +=
(m_eBsh_p != nullptr) ? m_eBsh_p -> toString("E-BSH: ") : "-";
return str;
}
由于我只是对测试这个特定的 toString 函数感兴趣,因此我只想获得“m_propBsh_p”和“m_eBsh_p”的有效指针。我的目标/尝试如下:
//Assuming to have mocked class for pointers
std::shared_ptr<MockedBshClass> m_mockEBsh_p;
std::shared_ptr<MockedBshClass> m_mockPropBsh_p;
TEST_F(FooTest, toStringBshInfoPass)
{
std::string eBshAndpBshStr = "eBshAndpBshStr";
ON_CALL(*m_mockPropBsh_p, toString(_)).WillByDefault(Return(eBshAndpBshStr));
ON_CALL(*m_mockEBsh_p, toString(_)).WillByDefault(Return(eBshAndpBshStr ));
//EXPECT_CALL((*m_mockPropBsh_p), toString(_)).Times(1);
//EXPECT_CALL((*m_mockEBsh_p), toString(_)).Times(1);
//Call mock or some fake function which makes m_propBsh_p & m_eBsh_p valid.
foo->makePtrValidAgain(); //however this is a complex function which bring more callbacks and complexity and i do not want to call, instead i want to have some fake/mocked function which just gives me valid pointers
EXPECT_THAT(foo->toString(""),HasSubstr(eBshAndpBshStr+eBshAndpBshStr));
}
以下是 Foo 类和指针的位背景:
Class Foo : fooParent..
{
...
void makePtrValidAgain();
std::string toString();
..
typedef std::shared_ptr<BshClass> m_propBsh_p;
typedef std::shared_ptr<BshClass> m_eBsh_p;
...
};
void Foo::makePtrValidAgain()
{
...
auto someFactory = m_dependencyContainer->get<bssh::SomeFactory>();
assert(someFactory);
auto nextTask = [this](std::uint32_t dummy){runAfterFoo();};
m_propBsh_p = someFactory->create(callback, nextTask);
m_propBsh_p->execute();
...
//and same happens with m_eBsh_p
return;
}
我不确定,避免使用 gmock/gtest 测试这种简单函数的复杂性的最佳方法是什么,我的目的是拥有如上所述的有效指针。
【问题讨论】:
标签: c++ factory factory-pattern googlemock gmock