是否可以使用事务创建 SQL SERVER 函数答案

【问题标题】：Is it possible to create SQL SERVER Function using transaction是否可以使用事务创建 SQL SERVER 函数
【发布时间】：2023-03-04 14:08:01
【问题描述】：

我有一个简单的脚本，它基本上做了很多数据库操作。现在我需要升级数据库，我需要在同一个事务中创建函数。

BEGIN TRY --Start the Try Block..

    BEGIN TRANSACTION -- Start the transaction..
        -- HERE I need to add one function like
        IF  EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[FuctionTest]') AND type in (N'FN', N'IF', N'TF', N'FS', N'FT'))
DROP FUNCTION [dbo].[FuctionTest]
GO
CREATE FUNCTION FuctionTest 
(   
    @inputVal int
)
RETURNS int
AS
BEGIN
    RETURN (Select Id from [dbo].[test] where Id=@inputVal)
END

        UPDATE MyChecking SET Amount = Amount - @Amount

            WHERE AccountNum = @AccountNum

        UPDATE MySavings SET Amount = Amount + @Amount

            WHERE AccountNum = @AccountNum

    COMMIT TRAN -- Transaction Success!

END TRY

BEGIN CATCH

    IF @@TRANCOUNT > 0

        ROLLBACK TRAN --RollBack in case of Error

我将如何完成这项工作？我不想使用单独的脚本来创建函数。

【问题讨论】：

标签： sql-server tsql function transactions try-catch

【解决方案1】：

是的，使用EXEC('...') 喜欢：

--list all functions named like '%test_function%', which will not find any
SELECT [name] FROM sys.objects WHERE [name] like '%test_function%'

--create a function named 'test_function1'
exec ('create function [dbo].[test_function1] (@x int) returns varchar(50) as BEGIN return convert(varchar(50),@x)+''!'' END')

begin transaction

--create a function 'test_function2', which will be rolled back
exec ('create function [dbo].[test_function2] (@x int) returns varchar(50) as BEGIN return convert(varchar(50),@x)+''!!!!'' END')

rollback

--show the functions named like '%test_function%'
--which will only find 'test_function1', since 'test_function2'
--was rolled back
SELECT [name] FROM sys.objects WHERE [name] like '%test_function%'

输出：

name
-----------------------

(0 row(s) affected)

name
-------------------------
test_function1

(1 row(s) affected)

EDIT 显示一个开始尝试块....

BEGIN TRY

    --list all functions named like '%test_function%', which will not find any
    SELECT [name] FROM sys.objects WHERE [name] like '%test_function%'

    --create a function named 'test_function1'
    exec ('create function [dbo].[test_function1] (@x int) returns varchar(50) as BEGIN return convert(varchar(50),@x)+''!'' END')

    begin transaction

    --create a function 'test_function2', which will be rolled back
    exec ('create function [dbo].[test_function2] (@x int) returns varchar(50) as BEGIN return convert(varchar(50),@x)+''!!!!'' END')

    RAISERROR('force catch!',16,1) --send control to the BEGIN CATCH block

    --should never get here
    COMMIT 

END TRY
BEGIN CATCH

    IF XACT_STATE()!=0
    BEGIN
        ROLLBACK TRANSACTION
    END
    PRINT CASE WHEN ERROR_NUMBER() IS NOT NULL THEN 'Msg '+CONVERT(varchar(30),ERROR_NUMBER()) ELSE '' END+CASE WHEN ERROR_SEVERITY() IS NOT NULL THEN ', Level '+CONVERT(varchar(30),ERROR_SEVERITY()) ELSE '' END+CASE WHEN ERROR_STATE() IS NOT NULL THEN ', State '+CONVERT(varchar(30),ERROR_STATE()) ELSE '' END+CASE WHEN ERROR_PROCEDURE() IS NOT NULL THEN ', Procedure '+ERROR_PROCEDURE() ELSE '' END+CASE WHEN ERROR_LINE() IS NOT NULL THEN ', Line '+CONVERT(varchar(30),ERROR_LINE()) ELSE '' END+CASE WHEN ERROR_MESSAGE() IS NOT NULL THEN ', '+ERROR_MESSAGE() ELSE '' END
END CATCH


--show the functions named like '%test_function%'
--which will only find 'test_function1', since 'test_function2'
--was rolled back
SELECT [name] FROM sys.objects WHERE [name] like '%test_function%'

输出：

name
---------------------------------------------------

(0 row(s) affected)

Msg 50000, Level 16, State 1, Line 14, force catch!
name
---------------------------------------------------
test_function1

(1 row(s) affected)

【讨论】：

嗨 RacerX，如果上面存在 try/catch 块，您能否使用相同的脚本，即 try/catch 块将包含事务块，然后我需要在事务中使用该脚本。谢谢，小吃
RacerX：您的方法似乎取决于用户是否拥有足够的 CREATE 权限……对吗？
是的。使用EXEC 不会以任何方式绕过此要求。
@Tapas Mahata，我想不出为什么 begin try 块会导致它的行为有任何不同。为什么不试试看呢？
@Tapas Mahata，是的，它的工作原理相同，我对其进行了测试，并将编辑我的问题，显示开始尝试块...