TS 创建描述性较差的 .d.ts 文件

Question

我在 .ts 文件中有这个输入：

export const OverSizedItems = <{ [key: string]: OverSizedItemType }>{

  NONE: {
    factor: 1,
    count: 0,
    mooversNeeded: 1,
  },

  ONE: {
    factor: 1.01,
    count: 1,
    mooversNeeded: 4,
  },

  TWO: {
    factor: 1.03,
    count: 2,
    mooversNeeded: 4,
  },

  THREE_PLUS: {
    factor: 1.07,
    count: 5,
    mooversNeeded: 6,
  }

};

它转译为：

export declare const OverSizedItems: {
    [key: string]: OverSizedItemType;
};

但如果更改原件，并省略索引签名类型信息，我会得到这个，这就是我想要的：

export declare const OverSizedItems: {
    NONE: {
        factor: number;
        count: number;
        mooversNeeded: number;
    };
    ONE: {
        factor: number;
        count: number;
        mooversNeeded: number;
    };
    TWO: {
        factor: number;
        count: number;
        mooversNeeded: number;
    };
    THREE_PLUS: {
        factor: number;
        count: number;
        mooversNeeded: number;
    };

};

枚举在这里不起作用，因为枚举不能指向对象。

那么我该怎么做才能添加索引签名但保留所有值？

Answer 1

我能想到的最好办法是使用 Record 类型，所有键都写在一个联合中，如下所示：

type OverSizedItemKey = "NONE" | "ONE" | "TWO" | "THREE_PLUS"

export const OversizedItems: Record<OverSizedItemKey, OverSizedItemType> = {
  // ...
}

Record 使用 mapped type，因此请确保您熟悉它以了解其工作原理/原因。