将对象数组转换为新数组及其子对象

Question

我有一个这样的数组

var data = [
    {
        name: "Movies", info: "category_name",
        content: [
            { name: "Interstellar", info: "category_data" },
            { name: "Dark Knight", info: "category_data" },
        ]
    },
    {
        name: "Music", info: "category_name",
        content: [
            { name: "Adams", info: "category_data" },
            { name: "Nirvana", info: "category_data" },
        ]
    },
    {
        name: "Places", info: "category_name",
        content: [
            { name: "Jordan", info: "category_data" },
            { name: "Punjab", info: "category_data" },
        ]
    },
]

想把它改造成这样的

var transformedArray= [
  { name: "Movies", info: "category_name" },
  { name: "Interstellar", info: "category_data" },
  { name: "Dark Knight", info: "category_data" },
  { name: "Music", info: "category_name" },
  { name: "Adams", info: "category_data" },
  { name: "Nirvana", info: "category_data" },
  { name: "Places", info: "category_name" },
  { name: "Jordan", info: "category_data" },
  { name: "Punjab", info: "category_data" },
]

我不知道适合这种情况的关键字是什么， 我已经尝试将它映射到新数组中，但它与我预期的不同

var newArr = []

var manipulate = data.map(item => {
    return (
        newArr.push(item),
        new1.map(items => {
            return (
                new1.push(items)
            )
        })
    )
})

那么如何将“数据”操作成“transformedArray”

Answer 1

使用Array.prototype.flatMap()。如果您的浏览器或 Node.js 版本尚未原生支持此功能，您可以在下面包含一个简单的 polyfill，基于 the specification：

if (!Array.prototype.flatMap) {
  Object.defineProperty(Array.prototype, 'flatMap', {
    configurable: true,
    writable: true,
    value: function flatMap (callback, thisArg = undefined) {
      return this.reduce((array, ...args) => {
        const element = callback.apply(thisArg, args);

        if (Array.isArray(element)) array.push(...element);
        else array.push(element);

        return array;
      }, []);
    }
  });
}

const data = [{name:'Movies',info:'category_name',content:[{name:'Interstellar',info:'category_data'},{name:'Dark Knight',info:'category_data'}]},{name:'Music',info:'category_name',content:[{name:'Adams',info:'category_data'},{name:'Nirvana',info:'category_data'}]},{name:'Places',info:'category_name',content:[{name:'Jordan',info:'category_data'},{name:'Punjab',info:'category_data'}]}];
const transformedArray = data.flatMap(({ content, ...o }) => [o, ...content]);

console.log(transformedArray);

Answer 2

您可以使用reduce 方法和传播语法... 来做到这一点。

var data = [{"name":"Movies","info":"category_name","content":[{"name":"Interstellar","info":"category_data"},{"name":"Dark Knight","info":"category_data"}]},{"name":"Music","info":"category_name","content":[{"name":"Adams","info":"category_data"},{"name":"Nirvana","info":"category_data"}]},{"name":"Places","info":"category_name","content":[{"name":"Jordan","info":"category_data"},{"name":"Punjab","info":"category_data"}]}]

const result = data.reduce((r, {content, ...rest}) => {
  r.push({...rest}, ...content)
  return r;
}, []);

console.log(result);

您也可以使用concat 和reduce 代替展开语法。

var data = [{"name":"Movies","info":"category_name","content":[{"name":"Interstellar","info":"category_data"},{"name":"Dark Knight","info":"category_data"}]},{"name":"Music","info":"category_name","content":[{"name":"Adams","info":"category_data"},{"name":"Nirvana","info":"category_data"}]},{"name":"Places","info":"category_name","content":[{"name":"Jordan","info":"category_data"},{"name":"Punjab","info":"category_data"}]}]
const result = data.reduce((r, {content, ...rest}) => r.concat(rest, content), []);
console.log(result);