电话无法解决

Question

我在 BroadcastReceiver 中使用了此代码，但此处无法解析 Telephony。如何在 BroadcastReceiver 中使用 Telephony？我认为是因为在 BroadcastReceiver 中使用了它。

public class SmsFilter extends BroadcastReceiver {
 SharedPreferences preferences = null ;
    Context context;
    static ContentResolver ctx;
  String text;


@Override
public void onReceive(final Context context, Intent intent) {


    if(android.os.Build.VERSION.SDK_INT>= 4.0){

        Log.i("LOG", "this is: "+Build.VERSION.RELEASE);    
         final String myPackageName = context.getPackageName();
         if (!Telephony.Sms.getDefaultSmsPackage(this).equals(myPackageName)) {
             // App is not default.
             // Show the "not currently set as the default SMS app" interface
             View viewGroup = findViewById(R.id.not_default_app);
             viewGroup.setVisibility(View.VISIBLE);

             // Set up a button that allows the user to change the default SMS app
             Button button = (Button) findViewById(R.id.change_default_app);
             button.setOnClickListener(new View.OnClickListener() {
                 public void onClick(View v) {
                     Intent intent =
                             new Intent(Telephony.Sms.Intents.ACTION_CHANGE_DEFAULT);
                     intent.putExtra(Telephony.Sms.Intents.EXTRA_PACKAGE_NAME, 
                             myPackageName);
                     context.startActivity(intent);
                 }
             });
         } else {
             // App is the default.
             // Hide the "not currently set as the default SMS app" interface
             View viewGroup = findViewById(R.id.not_default_app);
             viewGroup.setVisibility(View.GONE);
         }





            }}}

Answer 1

你需要Telephony.Sms.getDefaultSmsPackage(context)，而不是Telephony.Sms.getDefaultSmsPackage(this)。在您的情况下，this 指的是 BroadcastReceiver，并且该方法需要一个 context 参数。