【发布时间】:2019-06-09 20:15:41
【问题描述】:
我想访问 Square Catalog API 使用其 PHP SDK 返回的返回对象中的特定字段。我正在使用 listCatalog 选项,它返回显示所有项目和所有相应值的整个对象。但是,我需要做些什么来进一步分解它以提取某些值,例如 name 和 id?
我尝试了不同的方法来深入研究对象并提取以下字段:
$id = $result->getObjects()->getId()
但是,这会使程序崩溃。任何关于我做错了什么的想法都将不胜感激。
$api_instance = new SquareConnect\Api\CatalogApi();
$cursor = ""; // string | The pagination cursor returned in the previous response. Leave unset for an initial request. See [Pagination]. (/basics/api101/pagination) for more information.
$types = "Item,Item_Variation,Category"; // string | An optional case-insensitive, comma-separated list of object types to retrieve, for example `ITEM,ITEM_VARIATION,CATEGORY,IMAGE`. The legal values are taken from the [CatalogObjectType](#type-catalogobjecttype) enumeration, namely `ITEM`, `ITEM_VARIATION`, `CATEGORY`, `DISCOUNT`, `TAX`, `MODIFIER`, `MODIFIER_LIST`, or `IMAGE`.
try {
$result = $api_instance->listCatalog($cursor, $types);
$id = $result->getObjects();
print_r ($id);
} catch (Exception $e) {
echo 'Exception when calling CatalogApi->listCatalog: ', $e- >getMessage(), PHP_EOL;
}
【问题讨论】: