【发布时间】:2020-01-20 18:43:37
【问题描述】:
我有一段代码,可以根据观察到的时间为散点图点提供各种颜色。这是按照以下代码完成的:
color=listCoords.index.hour
在上下文代码中:
return go.Figure(
data=[
# Data for all observations based on date and time
Scattermapbox(
lat=listCoords["Lat"],
lon=listCoords["Lon"],
mode="markers",
hoverinfo="text + lat + lon",
text=listCoords.index.hour,
marker=dict(
showscale=True,
color=listCoords.index.hour,
opacity=np.where((listCoords['Threat'] == '3'), 0.1, 0.7),
size=np.where((listCoords['Threat'] == '3'), 20, 7),
colorscale=[
[0, "#F4EC15"],
[0.04167, "#DAF017"],
[0.0833, "#BBEC19"],
[0.125, "#9DE81B"],
[0.1667, "#80E41D"],
[0.2083, "#66E01F"],
[0.25, "#4CDC20"],
[0.292, "#34D822"],
[0.333, "#24D249"],
[0.375, "#25D042"],
[0.4167, "#26CC58"],
[0.4583, "#28C86D"],
[0.50, "#29C481"],
[0.54167, "#2AC093"],
[0.5833, "#2BBCA4"],
[1.0, "#613099"],
],
colorbar=dict(
title="Time of<br>Day",
x=0.93,
xpad=0,
nticks=24,
tickfont=dict(color="#d8d8d8"),
titlefont=dict(color="#d8d8d8"),
thicknessmode="pixels",
),
),
),
我想把'color='改成:
color=np.where((listCoords['Threat'] == '3'), 'red', listCoords.index.hour)
如果点的“威胁”值等于“3”,则这些点变为“红色” 否则“颜色”应该只是 'listCoords.index.hour'
但是这个新的代码更新给出了:
ValueError:
Invalid element(s) received for the 'color' property of scattermapbox.marker
Invalid elements include: ['4', '4', '4', '4', '4', '4', '4', '4', '4', '4']
The 'color' property is a color and may be specified as:
- A hex string (e.g. '#ff0000')
- An rgb/rgba string (e.g. 'rgb(255,0,0)')
- An hsl/hsla string (e.g. 'hsl(0,100%,50%)')
- An hsv/hsva string (e.g. 'hsv(0,100%,100%)')
- A named CSS color:
aliceblue, antiquewhite, aqua, aquamarine, azure,
beige, bisque, black, blanchedalmond, blue,
blueviolet, brown, burlywood, cadetblue,
chartreuse, chocolate, coral, cornflowerblue....
问题:所以是的,它显然需要 CSS 颜色。但是看到最初的'color='确实认为
listCoords.index.hour一个值,如果不是,我怎样才能让这个项目再次考虑该值 “红色”?
【问题讨论】:
标签: python css plotly-dash