如何允许 UITapGestureRecognizer 检测 Web 视图上的点击？

Question

我在 Xcode 中为 iPhone 制作了网络浏览器，要退出网络浏览器并返回主页面，请在屏幕上点按 3 次，但手势仅适用于顶部和底部的工具栏屏幕上，但不在网络视图上。

我能做什么？

这是我的代码

.h 文件

#import <UIKit/UIKit.h>

@interface Internet : UIViewController {


IBOutlet UIWebView *webview;
IBOutlet UIBarButtonItem *forwards;
IBOutlet UIBarButtonItem *backwards;
IBOutlet UITextField *URLTextField;

}

- (IBAction)share:(id)sender;

- (IBAction)returnKeyPressed:(id)sender;
- (IBAction)google:(id)sender;
- (IBAction)reload:(id)sender;
- (IBAction)forwardsButton:(id)sender;
- (IBAction)backwardsButton:(id)sender;



@end

.m 文件（仅显示相关代码）

- (void)viewDidLoad
{
    [super viewDidLoad];

    // Do any additional setup after loading the view.
    NSString *homePageString = @"http://www.google.com";
    NSURL *homePage = [NSURL URLWithString:homePageString];
    NSURLRequest *requestHomePage = [NSURLRequest requestWithURL:homePage];
    [webview loadRequest:requestHomePage];
    forwards.enabled = NO;
    backwards.enabled = NO;
    UIAlertView *touchHelp = [[UIAlertView alloc] initWithTitle:@"Alert, Please Read" message:@"To go back to the App Selection Page please anywhere on the top or bottom toolbar three times" delegate:nil cancelButtonTitle:@"Okay" otherButtonTitles:nil, nil];
    [touchHelp show];
    UITapGestureRecognizer *tapRecognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapDetected:)];
    tapRecognizer.numberOfTapsRequired = 3;
    [self.view addGestureRecognizer:tapRecognizer];
}

- (void)tapDetected:(UITapGestureRecognizer *)tapRecognizer {
    [self dismissViewControllerAnimated:YES completion:nil];
}

Answer 1

实现shouldRecognizeSimultaneouslyWithGestureRecognizer委托并返回YES。

实现细节：

将UIGestureRecognizerDelegate 协议添加到您的.h 文件中

@interface ViewController : UIViewController <UIGestureRecognizerDelegate>

将此委托添加到您的 .m 文件中

-(BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer 
 {
    return YES
 }