C# CurlSharp EasyGet - 如何获取字符串结果

Question

我正在使用此代码发出 EasyGet 请求。有人知道如何获取字符串结果吗？

using CurlSharp;
public static void CurlSharpGet(string url, bool useHttp2 = true)
    {
        Curl.GlobalInit(CurlInitFlag.All);

        try
        {
            if (useHttp2)
            {
                using (var easy = new CurlEasy())
                {
                    easy.Url = url;
                    easy.WriteFunction = OnWriteData;
                    easy.HttpVersion = CurlHttpVersion.Http2_0;
                    easy.SslVerifyPeer = false;
                    easy.SslVerifyhost = false;
                    easy.Perform();
                    Console.WriteLine(easy.Perform());
                }
            }
            else
            {
                using (var easy = new CurlEasy())
                {
                    easy.Url = url;
                    easy.WriteFunction = OnWriteData;
                    easy.Perform();
                    Console.WriteLine(easy.Perform());
                }
            }
        }
        finally
        {
            Curl.GlobalCleanup();
        }
    }

    public static Int32 OnWriteData(byte[] buf, Int32 size, Int32 nmemb, object data)
    {
        Console.Write(Encoding.UTF8.GetString(buf));
        return size * nmemb;
    }

理想情况下，我希望有这样的东西：

public static string CurlSharpGet(string url, bool useHttp2 = true)
    {
        //my fixed code here
    }

使用 httpclient 或 webresponse 无法完成我正在做的事情的性质。对于我应该如何让上述代码返回字符串结果的任何建议，我将不胜感激。谢谢

Answer 1

如果您尝试从该方法中获取字符串结果，则必须将关键字 void 设置为 string。但我不认为那是你要问的，所以我在这里可能没用。