【发布时间】：2016-07-07 12:57:18
【问题描述】：
我的程序首先要求用户输入客户编号。这是在按下提交 1 按钮时实现的。然后这个客户号用于从数据库中提取信息并显示它。然后必须更改此客户的地址，以便在第二个表单上要求此更改并按下提交 2 按钮。
问题是：
- 当按下提交 2 按钮时，客户编号从
enter customer no框中消失，显示的信息也消失。 - 变量
$custno已失去其值。我需要这个变量来更新数据库。
为什么会这样？
我什至将 POST 用于submit 1 REQUEST METHOD，GET 用于submit 2 REQUEST METHOD。
这是我使用的代码：
<!DOCTYPE html>
<html>
<body>
<?php
$custno=""; $custexists=1; // $custexists=1 means the customer exists in the database
$newaddress1=""; $newaddress2="";
if ($_SERVER["REQUEST_METHOD"] == 'POST' ) {
if (isset ($_POST["submit1"])) {$custno=$_POST["cust"];
goprintcust($custno,$custexists,$newaddress1,$newaddress2);}}
?>
<div style="position: fixed; left: 14px; top: 10px;">
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
<br>
<label>Enter Customer No. <input type="number" name="cust" min="1" value="<?php echo $custno; ?>"/></label>
<br>
<input type="submit" name="submit1" value="Submit 1"/><br>
</form>
<?php
function goprintcust($custno,$custexists,$newaddress1,$newaddress2) {
?><div style="position: relative; left: 8px; top:80px;"><?php
// Here search database for $custno and if it exists set $custexists=1
if ($custexists==1) {echo "current data for customer $custno is as follows ..."; // Print the current customer data from the database here
getnewinput($newaddress1,$newaddress2);}} // we assume the customer exists in the database
// so now get the new data to write into the database
function getnewinput($newaddress1,$newaddress2) {
?>
<div style="position: fixed; left: 14px; top: 60px;">
<table>
<form method="get" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>"">
<tr><td><label>New Address 1 :</td><td> <input type="text" name="newaddress1" value="<?php echo $newaddress1; ?>"/></label></td></tr>
<br>
<tr><td><label>New Address 2 :</td><td> <input type="text" name="newaddress2" value="<?php echo $newaddress2; ?>"/></label></td></tr>
<br>
<input type="hidden" name="cust" value="<?php echo $custno; ?>">
<tr><td><input type="submit" name="submit2" value="Submit 2"></td></tr><br>
</form>
</table>
<?php }
if ($_SERVER["REQUEST_METHOD"]=="GET") {
if (isset ($_GET["submit2"])) {
$newaddress1=$_GET["newaddress1"]; $newaddress2=$_GET["newaddress2"];
getnewinput($newaddress1,$newaddress2);
?><div style="position: absolute; left: 8px; top:130px;"><?php
// Here write the new Address into the database
echo "<br>"."Database updated for Customer No. ".$custno;
}}
?>
</body>
</html>
【问题讨论】：
-
第一次提交表单
Data A被提交，第二次提交表单Data B被提交，除非你也提交Data ATOGETHER WITHData B然后Data A丢失了。 （或将其存储在其他地方，例如 cookie 或会话）。