如果我按照正确的方式,编写 TFF 类型速记中描述的高级计算的方法是:
@tff.federated_computation(...)
def run_one_round(server_state, client_datasets):
weights_subset = tff.federated_map(subset_fn, server_state)
clients_weights_subset = tff.federated_broadcast(weights_subset)
client_models = tff.federated_map(client_training_fn,
(clients_weights_subset, client_datasets))
aggregated_update = tff.federated_aggregate(client_models, ...)
new_server_state = tff.federated_map(apply_aggregated_update_fn, server_state)
return new_server_state
如果这是真的,似乎大部分工作都需要在subset_fn 中进行,它获取服务器状态并返回全局模式权重的子集。通常,模型是tf.Tensor 的结构(list 或dict,可能是嵌套的),正如您所观察到的,它不能用作tf.gather_nd 或tf.tensor_scatter_nd_update 的参数。但是,它们可以逐点应用于使用tf.nest.map_structure 的张量结构。例如,从三个张量的嵌套结构中选择 [0, 0] 处的值:
import tensorflow as tf
import pprint
struct_of_tensors = {
'trainable': [tf.constant([[2.0, 4.0, 6.0]]), tf.constant([[5.0]])],
'non_trainable': [tf.constant([[1.0]])],
}
pprint.pprint(tf.nest.map_structure(
lambda tensor: tf.gather_nd(params=tensor, indices=[[0, 0]]),
struct_of_tensors))
>>> {'non_trainable': [<tf.Tensor: shape=(1,), dtype=float32, numpy=array([1.], dtype=float32)>],
'trainable': [<tf.Tensor: shape=(1,), dtype=float32, numpy=array([2.], dtype=float32)>,
<tf.Tensor: shape=(1,), dtype=float32, numpy=array([5.], dtype=float32)>]}