列出重复超过 4 次的值答案

【问题标题】：list values that are duplicated more than 4 times列出重复超过 4 次的值
【发布时间】：2022-01-24 00:47:30
【问题描述】：

我在 2 个表之间进行连接，它们给我带来了有关系的 number_phone，并且我带来了这些重复的时间，但是，我试图为计数设置一个条件，以便它只列出那些重复超过 4 次，我尝试使用帐户，它使我的计数器全部为空。值得一提的是，我没有为计数占用 group by，因为它给我带来了错误的值。

SELECT
    REPLACE(REPLACE(t.id_contrato,'0999',''),'0998','')as contrato , 
    t.num_telefono,
    conc.valor_actual,
    (
        SELECT COUNT('x') 
        FROM TBL_TELEFONO ct 
        WHERE ct.num_telefono = t.num_telefono
        AND ct.origen_tel='TELEFONO CONTRATO' 
        -- HAVING COUNT(*) > 4 
    ) as counter 
FROM TBL_TELEFONO t
INNER JOIN  CAM_TBL_ALERTA_CONCENTRADO conc ON t.num_telefono = conc.valor_actual 
WHERE id_contrato IS NOT NULL
AND id_contrato NOT IN ('N/A')
ORDER BY 4 DESC

如何只列出重复超过 4 次的那些？

【问题讨论】：

您可能需要分组但电话，添加have子句并通过电话将主查询与子查询相关联。

标签： sql oracle

【解决方案1】：

我不喜欢在没有示例数据的情况下调试代码，因此我将尝试在 Scott 的示例 EMP 表中对其进行说明。 “工作”就像您的“电话号码”一样。

SQL> select deptno, ename, job
  2  from emp
  3  order by job;

    DEPTNO ENAME      JOB
---------- ---------- ---------
        20 SCOTT      ANALYST    --> 2 analysts
        20 FORD       ANALYST
        10 MILLER     CLERK      --> 4 clerks
        30 JAMES      CLERK
        20 SMITH      CLERK
        20 ADAMS      CLERK
        30 BLAKE      MANAGER    --> 3 managers
        20 JONES      MANAGER
        10 CLARK      MANAGER
        10 KING       PRESIDENT  --> 1 president
        30 TURNER     SALESMAN   --> 4 salesmen
        30 MARTIN     SALESMAN
        30 WARD       SALESMAN
        30 ALLEN      SALESMAN

14 rows selected.

SQL>

据此，我们想获取所有的文员和销售员，因为他们有 4 个（或更多）。

代替count聚合函数，使用count的分析形式：

SQL> select deptno, ename, job,
  2    count(*) over (partition by job) cnt
  3  from emp
  4  order by job;

    DEPTNO ENAME      JOB              CNT
---------- ---------- --------- ----------
        20 SCOTT      ANALYST            2
        20 FORD       ANALYST            2
        10 MILLER     CLERK              4
        30 JAMES      CLERK              4
        20 SMITH      CLERK              4
        20 ADAMS      CLERK              4
        30 BLAKE      MANAGER            3
        20 JONES      MANAGER            3
        10 CLARK      MANAGER            3
        10 KING       PRESIDENT          1
        30 TURNER     SALESMAN           4
        30 MARTIN     SALESMAN           4
        30 WARD       SALESMAN           4
        30 ALLEN      SALESMAN           4

14 rows selected.

SQL>

现在事情变得更容易了：将该查询用作 CTE（或子查询），并应用 where 子句：

SQL> with temp as
  2    (select deptno, ename, job,
  3       count(*) over (partition by job) cnt
  4     from emp
  5    )
  6  select deptno, ename, job
  7  from temp
  8  where cnt >= 4
  9  order by job;

    DEPTNO ENAME      JOB
---------- ---------- ---------
        10 MILLER     CLERK
        30 JAMES      CLERK
        20 SMITH      CLERK
        20 ADAMS      CLERK
        30 TURNER     SALESMAN
        30 MARTIN     SALESMAN
        30 WARD       SALESMAN
        30 ALLEN      SALESMAN

8 rows selected.

SQL>

应用于您的查询（同样，没有任何样本数据无法对其进行测试）：

with temp as
  (select
     replace(replace(t.id_contrato,'0999',''),'0998','')as contrato , 
     t.num_telefono,
     conc.valor_actual,
     count(*) over (partition by t.num_telefono) as counter 
   from tbl_telefono t
   inner join  cam_tbl_alerta_concentrado conc on t.num_telefono = conc.valor_actual 
   where id_contrato is not null
     and id_contrato not in ('N/A')
  )
select contrato, num_telefono, valor_actual
from temp
where counter >= 4;

【讨论】：

谢谢，成功了。
不客气。

【解决方案2】：

加入超过 4 个的选择

SELECT
    REPLACE(REPLACE(t.id_contrato,'0999',''),'0998','')as contrato , 
    t.num_telefono,
    conc.valor_actual,
    ct.counter 
FROM TBL_TELEFONO t
INNER JOIN (
    SELECT num_telefono, COUNT(*) AS counter
    FROM TBL_TELEFONO  
    WHERE origen_tel='TELEFONO CONTRATO' 
    GROUP BY num_telefono
    HAVING COUNT(*) > 4 
) ct 
   ON ct.num_telefono = t.num_telefono
INNER JOIN CAM_TBL_ALERTA_CONCENTRADO conc 
   ON t.num_telefono = conc.valor_actual 
WHERE id_contrato IS NOT NULL
  AND id_contrato NOT IN ('N/A')
ORDER BY ct.counter DESC

【讨论】：

【解决方案3】：

将查询包装在另一个中以仅在 count > 4 时返回

select *
from (
    <your query, but without order by>
) x
where count > 4
order by count desc

【讨论】：