【发布时间】:2020-12-29 23:21:26
【问题描述】:
我正在尝试通过 SendGrid API 使用 Django 动态电子邮件模板。我知道已经有一些线程在这方面,但是,我无法让这些工作。
我有一个基本模板,其中包含一些基于我希望通过电子邮件发送给用户的搜索的动态变量。尽管应用了我在此处的许多其他线程中看到的内容,但除了 HTML 始终呈现在文本中之外,这都是有效的。
如果有任何帮助,将不胜感激。
Views.py
def customer_selections_sent(request):
#make=request.POST['makeselection']
if request.method == 'GET':
current_site = get_current_site(request)
emailto = request.user.email_user
user = request.user.username
#call session values from SearchInventory function
modelvalue =request.session.get('modelvalue')
makevalue =request.session.get('makevalue')
subject = 'ShowVroom Selections'
#create variables to be used in the email template
Email_Vars = {
'user': user,
'make': makevalue,
'model': modelvalue,
'domain': current_site.domain,
}
#create the email msg
message = get_template('customer_selections_email.html').render(Email_Vars)
html_message = get_template('customer_selections_email.html').render(Email_Vars)
message.content_subtype = "html" # Main content is now text/html
#send email
request.user.email_user(subject,message)
#request.user.email_user(subject, html_message)
#return redirect('customer_selections_sent')
return render(
request,
'customer_selections_sent.html',
{
'title':'Deals are on the way',
'body':'We will email you shortly with more detail on your choices, you can respond to the dealers via the app until you agree to a viewing, test or purchase ',
'year':datetime.now().year,
}
)
send_mail(subject, message, 'Abc@xyz.org', emailto, fail_silently=False,html_message=html_message)
sg = SendGridAPIClient(os.environ.get('SENDGRID_API_KEY'))
response = sg.send(message)
#log respon
print(response.status_code)
print(response.body)
print(response.headers)
HTML 模板
<!DOCTYPE html>
<html lang="en">
{% load static %}
<head>
<meta charset="UTF-8" />
<meta name="viewport" content="width=device-width, initial-scale=1.0" />
<title>Your ShowVroom Selections</title>
<img align="left" src="Logo1.png" alt="ShowVroom">
</head>
<body>
Hi {{ user }},
Here are your search selections;
<Strong>
<br>Make; {{make}} </br>
<br>Model; {{model}} </br>
</Strong>
</body>
<foot>
<a href = "mailto:info@showvroom.ie?subject = Offer&body = Message">
Contact ShowVroom
</a>
</foot>
</html>
更新视图.PY
def customer_selections_sent(request):
if request.method == 'GET':
#User variables
emailto = request.user.email_user
user = request.user.username
#call session values from another function
modelvalue =request.session.get('modelvalue')
makevalue =request.session.get('makevalue')
subject = 'ShowVroom Selections'
#create variables to be used in the email template
Email_Vars = {
'user': user,
'make': makevalue,
'model': modelvalue,
#'offer': DisplayInventory.GaragePrice,
'domain': current_site.domain,
}
#create the email msg
message = get_template('customer_selections_email.html').render(Email_Vars)
html_message = get_template('customer_selections_email.html').render(Email_Vars)
message.content_subtype = "html" # Main content is now text/html
#Redirect to sent email Webpage
request.user.email_user(subject,message)
return render(
request,
'customer_selections_sent.html',
{
'title':'Deals are on the way',
'body':'We will email you shortly with more detail on your choices, you can respond to the dealers via the app until you agree to a viewing, test or purchase ',
'year':datetime.now().year,
}
)
#send email
send_mail(subject, message, 'email@domain.com', emailto, fail_silently=False,html_message=html_message)
sg = SendGridAPIClient(os.environ.get('SENDGRID_API_KEY'))
response = sg.send(message)
#log responses
print(response.status_code)
print(response.body)
print(response.headers)
【问题讨论】:
标签: django django-templates sendgrid email