Azure SendGrid SMTP 给出 500 错误答案

【问题标题】：Azure SendGrid SMTP giving 500 errorAzure SendGrid SMTP 给出 500 错误
【发布时间】：2018-05-01 19:56:55
【问题描述】：

我正在尝试在我的 Azure 应用程序上实现 SendGrid，但它一直在浏览器上抛出 HTTP ERROR 500。我正在使用完全相同的代码遵循本教程，但输入了我的值。我似乎找不到任何关于如何解决这个问题的信息，以及我可以判断这些值是正确的。错误发生在创建Swift_SmtpTransport::newInstance() 方法时。

这里是sn-p的代码：

$text = "Hi!\nHow are you?\n";
$html = "<html>
    <head></head>
    <body>
        <p>Hi!<br>
            How are you?<br>
        </p>
    </body>
    </html>";
// This is your From email address
$from = array('someone@example.com' => 'Test User');
// Email recipients
$to = array(
    'toemail@email.com' => 'Elite Email Address'
);
// Email subject
$subject = 'Example PHP Email';

// Login credentials
$username = 'myusernamefromazure';
$password = 'mypassword';

// Setup Swift mailer parameters
$transport = Swift_SmtpTransport::newInstance('smtp.sendgrid.net', 587); <-- this is where the error is thrown...

有人可以帮我解决这个问题吗？

【问题讨论】：

标签： php azure sendgrid

【解决方案1】：

sendgrid 网站上的教程看起来有点不同：

<?php
// using SendGrid's PHP Library
// https://github.com/sendgrid/sendgrid-php

// If you are using Composer (recommended)
require 'vendor/autoload.php';

// If you are not using Composer
// require("path/to/sendgrid-php/sendgrid-php.php");

$from = new SendGrid\Email("Example User", "test@example.com");
$subject = "Sending with SendGrid is Fun";
$to = new SendGrid\Email("Example User", "test@example.com");
$content = new SendGrid\Content("text/plain", "and easy to do anywhere, even with PHP");
$mail = new SendGrid\Mail($from, $subject, $to, $content);

$apiKey = getenv('SENDGRID_API_KEY');
$sg = new \SendGrid($apiKey);

$response = $sg->client->mail()->send()->post($mail);
echo $response->statusCode();
print_r($response->headers());
echo $response->body();

来源： https://sendgrid.com/docs/Integrate/Code_Examples/v3_Mail/php.html

【讨论】：

我试过了，现在在$from = new SendGrid\Email("Example User", "test@example.com");出现同样的错误