SQL在两列中选择具有不同值的行

Question

我有 4-5 个表的数据库。 我正在收集这样的数据

N |名称_ |索尼_ |萨夫多 |福伊达 | Val(货币) 1 |苹果 | 5公斤 | 5000 | 500 |乌兹别克斯坦 2 |香蕉| 4公斤 | 7000 | 800 |乌兹别克斯坦 3 |桃子 | 2公斤 | 2 | 0.2 |美元

我想将 Currency 列分开，如下所示

N |名称_ |索尼_ |萨夫多 |福伊达 | VAL1 | VAL2 1 |苹果 | 5公斤 | 5000 | 500 |乌兹别克斯坦 | 2 |香蕉| 4公斤 | 7000 | 800 |乌兹别克斯坦 | 3 |桃子 | 2公斤 | 2 | 0.2 | |美元

这是我的 SQL 代码。

select  s.nom_ , sum(o.soni_) as soni_ ,
   sum(o.soni_*(select narx_ from toper where id_=o.id_ )) as savdo_, 
   sum((o.soni_*o.narx_-o.soni_* (select narx_ from toper where id_=o.id_op ))) as foyda_,
   (select nom_ from tsinf where id_=o.id_v) as val_ 
      from toper o left join tsf f on o.id_sf=f.id_  
      left join tsinf s on o.id_s=s.id_  
where (f.date_>=date('2020-01-01')) and (f.date_<=date('2020-04-04')) 
and f.oper_=-1  group by id_s, id_v 

Answer 1

我会将子查询移至FROM 子句（使用LEFT JOIN）。那么拆分就是两个CASE表达式：

select s.nom_ , sum(o.soni_) as soni_,
       sum(o.soni_*(select narx_ from toper where id_=o.id_ )) as savdo_, 
       sum((o.soni_*o.narx_-o.soni_* (select narx_ from toper where id_=o.id_op ))) as foyda_,
        (case when sv.nom_1 = 'UZS' then sv.nom_1 end) as uzs,
        (case when sv.nom_1 = 'USD' then sv.nom_1 end) as usd
from toper o left join
     tsf f
     on o.id_sf = f.id_  left join
     tsinf s
     on o.id_s = s.id_ left join
     tsinf sv
     on sv.id_ = o.id_v
where f.date_ >= date('2020-01-01') and
      f.date_ <= date('2020-04-04') and 
      f.oper_ = -1 
group by id_s, id_v ;

我还建议删除toper 的子查询，但这将是另一个问题。

Answer 2

将您的查询放在 CTE 中，然后使用 CASE 表达式选择 2 列：

with cte as (
  select s.nom_ , sum(o.soni_) as soni_ ,
    sum(o.soni_*(select narx_ from toper where id_=o.id_ )) as savdo_, 
    sum((o.soni_*o.narx_-o.soni_* (select narx_ from toper where id_=o.id_op ))) as foyda_,
    (select nom_ from tsinf where id_=o.id_v) as val_ 
  from toper o left join tsf f on o.id_sf=f.id_  
  left join tsinf s on o.id_s=s.id_  
  where (f.date_>=date('2020-01-01')) and (f.date_<=date('2020-04-04')) 
  and f.oper_=-1  
  group by id_s, id_v
)
select nom_, soni, savdo, foyda_, 
  case when val_ = 'UZS' then val_ end as Val1,
  case when val_ = 'USD' then val_ end as Val2 
from cte

但你应该知道条件：

where (f.date_>=date('2020-01-01')) and (f.date_<=date('2020-04-04'))

将您的 left 连接更改为 tsf 到 inner 连接。如果结果是你所期望的，那很好。如果不将这些条件移至 ON 子句。

此外，如果关系是 1:1，则可以使用 joins，而不是您在选择列表中使用的所有 select 语句。
试试这个：

select  
  s.nom_, 
  sum(o.soni_) as soni_,
  sum(o.soni_* o2.narx_) as savdo_, 
  sum((o.soni_*o.narx_-o.soni_* o3.narx_) as foyda_,
  case when s2.nom_ = 'UZS' then s2.nom_ end as Val1,
  case when s2.nom_ = 'USD' then s2.nom_ end as Val2 
from toper o 
left join toper o2 on o2.id_=o.id_
left join toper o3 on o3.id_=o.id_op
left join tsf f on o.id_sf=f.id_  
left join tsinf s on o.id_s=s.id_ 
left join tsinf s2 on o.id_v=s2.id_  
where (f.date_>=date('2020-01-01')) and (f.date_<=date('2020-04-04')) and f.oper_=-1  
group by id_s, id_v