Zabbix Json Api 获取主机或主机组的健康状况

Question

我目前正在尝试 Zabbix 2.4 json api 并且可以连接获取警报和触发器，但我无法找到一种方法来检查给定主机组是否不包含打开的错误并且因此是健康的。似乎存在一种简单的检查方法？我搜索了 stackoverflow、google 和 Zabbix 文档。关于解决这个问题的任何线索？以下请求给了我错误，但无法判断错误是否仍然存在。

{
"jsonrpc": "2.0",
"method": "alert.get",
"params": {
"output": "extend",
"groupids": "83",
"time_from": "1441065600"
},
"auth": "ZZZZZZZZZZZZZZZZZZZZZZZZZ",
"id": 1
}

更新：（已解决）

$resource = "http://zabbix/api_jsonrpc.php"

$body = '
{
"jsonrpc": "2.0",
"method": "trigger.get",
"params": {
    "active": 1,
    "only_true": "1",
    "monitord": 1,
    "selectGroups": 1,
    "output": "extend",
    "expandDescription": "1",
    "selectGroups": "1",
        "groupids": 83,     <----  this field changes :)
    "filter": {
        "value": 1,
        "priority": [3,4,5]    <----- filter off low prios
    },
    "sortfield": "priority",
    "sortorder": "DESC"
},
"auth": "ZZZZZZZZZZZZZZZZZZZZZZZZZ",
"id": 1
}
'
$result = Invoke-RestMethod -Method Post -Uri $resource -Body $body -ContentType "application/json"

$result.result

Answer 1

使用主机/组的活动触发器。我使用的一些代码：

zapi.trigger.get(only_true=1,
        skipDependent=1,
        monitored=1,
        active=1,
        output='extend',
        expandDescription=1,
        selectGroups=1,
        expandData='host',
        hostids=<host_id>,
        sortfield='priority',
        sortorder='DESC',
        filter={"value": 1, "priority": ['4','5']}
    )

https://www.zabbix.com/documentation/2.4/manual/api/reference/trigger/get