错误 SMTP 无法从 gmail 发送电子邮件

Question

我目前正在尝试使用 smtp 将电子邮件从我的 gmail 发送到另一个雅虎电子邮件地址。我从我的 Gmail 帐户启用了不太安全的应用程序。我也通过了 Gmail Captcha。我也尝试添加一个端口号（587、2525），但没有成功。我无法让代码工作。我在这里发布了我的代码，然后是错误消息。

奇怪的是，几个月前这对我有用！

import requests
from bs4 import BeautifulSoup
# import lxml
import smtplib

my_email = "MY_EMAIL@gmail.com"
password = "MY_PASSWORD"

URL = "https://www.amazon.com/Instant-Pot-Plus-60-Programmable/dp/B01NBKTPTS/ref=sr_1_1_sspa?crid=34PO9PKK0CUSX" \
      "&keywords=instant%2Bpot&qid=1639842722&sprefix=instant%2Caps%2C76&sr=8-1-spons&spLa=ZW5jcnlwdGVkUXVhbGlmaWV" \
      "yPUEyUlM1TDQ5N0RQS1VXJmVuY3J5cHRlZElkPUEwNzc4NTk5M0c2VVhTVlE1Q1lBTyZlbmNyeXB0ZWRBZElkPUEwMjE0NzMyNUlTVUg0V1" \
      "BYQTZWJndpZGdldE5hbWU9c3BfYXRmJmFjdGlvbj1jbGlja1JlZGlyZWN0JmRvTm90TG9nQ2xpY2s9dHJ1ZQ&th=1 "

TARGET_PRICE = 200

headers = {
    "User-Agent": "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_5) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/84.0.4147.125 Safari/537.36",
    "Accept-Language": "en-GB,en-US;q=0.9,en;q=0.8"
}

response = requests.get(URL, headers=headers)
website_html = response.text

print(response.status_code)

soup = BeautifulSoup(website_html, "lxml")

price = float(soup.find(id="attach-base-product-price").attrs["value"])
title = soup.find(id="productTitle").get_text()


# sending a notification email
if price <= TARGET_PRICE:
    message = f"{title} is now {price}"

    with smtplib.SMTP("smtp.gmail.com") as connection:
        connection.starttls()
        result = connection.login(my_email, password)
        connection.sendmail(
            from_addr=my_email,
            to_addrs="SOME_EMAIL@yahoo.com",
            msg=f"Subject:Amazon Price Alert!\n\n{message}\n{URL}"
        )

print("done")

错误信息

Traceback (most recent call last):
  File "/Users/Charaf/PycharmProjects/Intermediate+/AmazonPriceTracker/main.py", line 45, in <module>
    with smtplib.SMTP("smtp.gmail.com") as connection:
  File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/smtplib.py", line 255, in __init__
    (code, msg) = self.connect(host, port)
  File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/smtplib.py", line 341, in connect
    self.sock = self._get_socket(host, port, self.timeout)
  File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/smtplib.py", line 312, in _get_socket
    return socket.create_connection((host, port), timeout,
  File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/socket.py", line 843, in create_connection
    raise err
  File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/socket.py", line 831, in create_connection
    sock.connect(sa)
TimeoutError: [Errno 60] Operation timed out

Answer 1

您是否尝试过使用 Google 应用密码 (https://support.google.com/accounts/answer/185833?hl=en)？我刚刚用我的亚马逊价格检查器对其进行了测试，该检查器非常相似，并且可以在我的 Google 应用密码上运行。

不过这是我通常用来发送邮件的方式-

    def Send_Mail(email,password,remail): #Function for sending a mail to the user 
    server = smtplib.SMTP('smtp.gmail.com',587)
    server.ehlo()
    server.starttls()
    server.ehlo()
    
    server.login(email,password)
    
    body = f"Price Fell Down\n\nCheck -{url}"
    
    server.sendmail(email,remail,body)

Answer 2

Gmail 默认使用隐式 TLS 连接 (SSL)。

这意味着您不会升级与 starttls() 的 Gmail 连接。相反，您连接到不同的端口； ssl 端口465。

删除：

server.starttls()
server.ehlo()

..并且只保留一个server.ehlo()，当然连接到端口465。

在下面的列表中，您的代码应该适用于 Gmail 和 Rackspace 以外的任何服务。

• GMAIL.COM - 隐式 TLS 连接 (SSL)
• RACKSPACE.COM - 隐式 TLS 连接 (SSL)
• MAILTRAP.COM - 显式 TLS 连接 (STARTTLS)
• iCLOUD.COM - 显式 TLS 连接 (STARTTLS)
• 展望 - 显式 TLS 连接 (STARTTLS)
• OUTLOOK.COM - 显式 TLS 连接 (STARTTLS)
• YAHOO.COM - 显式 TLS 连接 (STARTTLS)
• MAIL.COM - 显式 TLS 连接 (STARTTLS)
• AOL.COM - 显式 TLS 连接 (STARTTLS)
• COMCAST.NET - 显式 TLS 连接 (STARTTLS)