如何在有限的时间内呈现刺激并仍然使用 Psychtoolbox 记录响应答案

【问题标题】：How to present stimulus for limited amount of time and still record response using Psychtoolbox如何在有限的时间内呈现刺激并仍然使用 Psychtoolbox 记录响应
【发布时间】：2018-08-24 18:51:52
【问题描述】：

对于我的实验，我想向参与者提供刺激和一些指示。然后 2 秒后，我希望刺激消失，但指示保持不变，直到参与者做出反应。参与者应该能够在刺激呈现后立即做出反应，并且在呈现刺激后最多 10 秒内做出反应。响应时间将被记录。

使用我当前的代码，参与者在 2 秒后（刺激消失后）才能做出反应。是否有某种方式让刺激仅出现 2 秒，而说明仍保留在屏幕上，但参与者能够在刺激呈现后立即做出反应？

%Show the instructions and the stimulus   
           Screen('DrawTexture', window, randFaceTexture2);
           DrawFormattedText(window, [instructions1], 'center', 600)

           stimTime = Screen('Flip', window);

           WaitSecs(2);

           %Stimulus disappears but instructions remain 
           DrawFormattedText(window, [instructions1], 'center', 600)
           Screen('Flip', window);

           if GetSecs() <= stimTime + 10
           keyIsDown = 0;
           startTime = GetSecs();
                while 1
                     [keyIsDown, secs, keyCode] = KbCheck;
                     FlushEvents('keyDown');
                     if keyIsDown
                          nKeys = sum(keyCode);
                               if nKeys == 1
                                    if keyCode(yes) || keyCode(no)
                                         reactionTime = 1000*(GetSecs - startTime);
                                         response = KbName(keyCode);
                                         Screen('Flip', window);
                                         break;
                                    elseif keyCode(escKey)
                                         ShowCursor;
                                         fclose(outfile);
                                         Screen('CloseAll');
                                    return 
                                    end 
                                    keyIsDown = 0;
                                    keyCode = 0;
                               end 
                     end 
                end 
           else 
                line3 = 'Sorry you''re out of time';
                DrawFormattedText(window, line3, 'center', 'center');
                Screen('Flip', window);
                keyIsDown = 0;
                rt = 0;
           end

【问题讨论】：

标签： octave response-time psychtoolbox

【解决方案1】：

不要使用WaitSecs() 来控制刺激在屏幕上显示的时间量，而是在经过适当的时间后在响应检查循环中关闭刺激。这是一个 sn-p，它显示了对上述代码的相关更改。我省略了您如何轮询响应的详细信息。顺便说一句，我认为您使用 'if GetSecs()

% time in seconds for the stimulus to remain onscreen
timeForStimulus = 2;
% time for the participant to respond, in seconds
timeToRespond = 10;

%Show the instructions and the stimulus
Screen('DrawTexture', window, randFaceTexture2);
DrawFormattedText(window, [instructions1], 'center', 600)

stimTime = Screen('Flip', window);
stimOnScreen = 1;

while GetSecs() <= (stimTime + timeToRespond)
    % turn the stimulus off, if the stim is on and the stim time has elapsed
    if (stimOnScreen == 1) && (GetSecs() > (stimTime + timeForStimulus))
        %Stimulus disappears but instructions remain
        DrawFormattedText(window, [instructions1], 'center', 600)
        Screen('Flip', window);
        stimOnScreen = 0;
    end

    % poll for keyboard response, etc.

end

【讨论】：