如何一直询问用户输入，直到我得到一个特定范围内的整数？

Question

我最近决定重新审视我大约 3 个月前制作的井字游戏，并以全新的眼光进行调试，特别是这个错误一直困扰着我。基本上，我有这个代码：

def player_choice(board):
    '''Asks the player for their next position, calls a func to check if it's free'''
    '''and returns the position if it's free for later use'''
    spot = None
    while spot not in range(1, 10) or not space_check(board, spot):
        try:
            spot = int(input("Choose your next position (1-9): "))
        except:
            print("Hmm, looks to me like your input was invalid")
        else:
            break
    return spot

这是更大方案中的一个函数，但破坏整个游戏的是我需要一个 整数 作为输入，严格在 1 到 10 之间的范围内。在尝试错误处理之前，我使用了一个 while 循环，如果给出了一个 str，它会不断要求一个 int：

spot = int(input("Choose your next position (1-9): "))
    while spot not in range (1, 10) or not space_check(board, spot):
        spot = int(input("Looks like the spot you're trying to choose is invalid!\nPlease choose another position (1-9): "))
    return spot

但后来我切换到这个版本，这里它不会接受 str 作为输入，但它会接受 1-10 范围之外的 int。我的问题是：我该怎么做才能使这项工作按我需要的方式进行，严格取一个介于 1 和 10 之间的整数并继续询问直到准确地提供此输入？

Answer 1

移动一些东西，这似乎有效。虽然不知道为什么else总是被触发...

def player_choice2(board):
    '''Asks the player for their next position, calls a func to check if it's free'''
    '''and returns the position if it's free for later use'''
    try:
        spot = int(input("Choose your next position (1-9): "))
    except:
        print("Hmm, looks to me like your input was invalid")
        spot = 0
    while spot not in range(1, 10) or not space_check(board, spot):
        try:
            spot = int(input("Choose your next position **  (1-9) **: "))
        except:
            print("Hmm, looks to me like your input was invalid")
        else:
            # This always fires...?
            print("Else....")
    return spot

Answer 2

spot = " "
while ord(spot) not in [49,58]:
    spot = input("Looks like the spot you're trying to choose is 
invalid!\nPlease choose another position (1-9): ")
    try:
       spot = ord(spot)
    excpet:
       spot = " "
return spot

我在这里所做的是检查点的 ascii 值应该是数字，数字是 1->49、2->50 等等。

Answer 3

也许这会有所帮助：

    def player_choice(board):
        '''Asks the player for their next position, calls a func to check if it's free'''
        '''and returns the position if it's free for later use'''
        spot = True
        while spot in range(1, 10) or not space_check(board, spot):
            try:
                spot = int(input("Choose your next position (1-9): "))
            except:
                break
        else:
            print("Hmm, looks to me like your input was invalid")
    
        return spot