函数内的循环

Question

为什么计算机没有变成 x ？在它通过循环并找到列表中而不是选择的东西之后，它不应该将 x 的值分配给计算机吗？

def ComputerMove(gameboard):
    for x in list:
        if x not in picked and x in list:
            computer = x 



list =  ("b2", "a1", "c3", "a3", "c1", "a2", "b3", "b1", "c2")

gameboard = {0:' ', 1:' ', 2:' ',
         3:' ', 4:' ', 5:' ',
         6:' ', 7:' ', 8:' ',
         }
picked = ("b2", "a1", "c3", "a3")
ComputerMove(gameboard) 

Answer 1

首先，list 是一个类型/保留，因此您不能将其用作变量名。其次，你拥有的是一个元组，而不是一个列表。所以，我转换了这些，这段代码似乎可以工作：

def ComputerMove(gameboard):
    for x in l:
        if x not in picked:
            computer = x
            return computer # not sure what do you want to do with this value?



l =  ["b2", "a1", "c3", "a3", "c1", "a2", "b3", "b1", "c2"]

gameboard = {0:' ', 1:' ', 2:' ',
         3:' ', 4:' ', 5:' ',
         6:' ', 7:' ', 8:' ',
         }
picked = ["b2", "a1", "c3", "a3"]
ComputerMove(gameboard) 
>>c1