【发布时间】:2021-12-08 23:37:08
【问题描述】:
用户使用内联键盘与我的 Telegram 机器人交互。一些按钮执行敏感的功能,我想在继续之前询问用户的确认。
例如:在主菜单中,用户在两个按钮Option 1 和Option 2 之间进行选择。点击后分别执行敏感函数do_action_1和do_action_2。
一个最小的工作示例如下:
from telegram import InlineKeyboardButton, InlineKeyboardMarkup, Update
from telegram.ext import Updater, CommandHandler, CallbackQueryHandler, CallbackContext
def start(update: Update, context: CallbackContext) -> None:
update.message.reply_text('Please choose:',
reply_markup = keyboard_main_menu())
def main_menu(update: Update, context: CallbackContext) -> None:
""" Displays the main menu keyboard when called. """
query = update.callback_query
query.answer()
query.edit_message_text(text = 'Please choose an option:',
reply_markup = keyboard_main_menu())
def keyboard_main_menu():
""" Creates the main menu keyboard """
keyboard = [
[InlineKeyboardButton("Option 1", callback_data='1'),
InlineKeyboardButton("Option 2", callback_data='2'),],
]
return InlineKeyboardMarkup(keyboard)
def do_action_1(update: Update, context: CallbackContext) -> None:
keyboard = [[InlineKeyboardButton("Main menu", callback_data='main')]]
reply_markup = InlineKeyboardMarkup(keyboard)
query = update.callback_query
query.answer()
query.edit_message_text(text=f"Selected option {query.data}\n"
f"Executed action 1.",
reply_markup=reply_markup)
def do_action_2(update: Update, context: CallbackContext) -> None:
keyboard = [[InlineKeyboardButton("Main menu", callback_data='main')]]
reply_markup = InlineKeyboardMarkup(keyboard)
query = update.callback_query
query.answer()
query.edit_message_text(text=f"Selected option {query.data}\n"
f"Executed action 2.",
reply_markup=reply_markup)
def main() -> None:
"""Run the bot."""
updater = Updater("TOKEN")
updater.dispatcher.add_handler(CommandHandler('start', start))
updater.dispatcher.add_handler(CallbackQueryHandler(main_menu, pattern='main'))
updater.dispatcher.add_handler(CallbackQueryHandler(do_action_1, pattern='1'))
updater.dispatcher.add_handler(CallbackQueryHandler(do_action_2, pattern='2'))
# Start the Bot
updater.start_polling()
print('started')
if __name__ == '__main__':
main()
现在,我想在单击Option 1 或Option 2 后插入一个中间步骤,显示键盘“Are you sure ?”有两个按钮 Yes 和 No。单击Yes 会根据用户在前一个键盘上的选择执行do_action_1 或do_action_2。单击No 将使用户返回主菜单。
我该怎么做?
【问题讨论】:
标签: python python-telegram-bot