Python，geopy杀死时间限制

Question

我从一个文件中读取了更多的千坐标，因为我想获得相关的国家。我试图杀死时间限制，但它还没有起作用，它在 150-160 坐标后停止。我可以处理吗？

#!/usr/bin/python
# -*- coding: utf-8 -*-
import os, sys


with open('alagridsor.txt') as f:
    lines = f.read().splitlines()    


for sor in range(1, 9271):
    print(sor) 

    koor = lines[sor]

    from geopy.geocoders import Nominatim
    from geopy.exc import GeocoderTimedOut

    geolocator = Nominatim()
    location = geolocator.reverse(koor, timeout=None)
    cim = location.raw['address']['country']

    print(cim)

    f = open('out.txt', 'a')
    f.write(cim.encode('utf8'))
    f.write("\n")

Answer 1

问题

1. 使用 f.read() 并省略 size 将导致文件的全部内容被读取并返回。如果文件是机器内存的两倍，您将遇到问题。
2. 总是在 for 循环中打开输出文件非常昂贵。

可能的解决方案

#!/usr/bin/python
# -*- coding: utf-8 -*-
import time
from geopy.geocoders import Nominatim

geolocator = Nominatim(timeout=None)
fobj_out = open('out.txt', 'a')
with open('alagridsor.txt') as fobj_in:
    for koor in fobj_in:
        location = geolocator.reverse(koor.rstrip())
        cim = location.raw['address']['country']
        fobj_out.write(cim.encode('utf8'))
        fobj_out.write("\n")
        time.sleep(0.5)     # delay 5 milli-seconds between each request
fobj_out.close()