【发布时间】:2016-09-19 08:51:13
【问题描述】:
我将AbstractQuery 定义为GraphObject 的子代:
class AbstractQuery(GraphObject):
__primarykey__ = "hash"
hash = Property()
projname = Property()
def __init__(self, hash):
self.hash = hash
self.projname = "" # TODO:initialize this
并遍历我(已经存在的)图中的所有SQLQuery 对象,并希望创建一个包含哈希的新AbstractQuery。任何SQLQuery 散列到确定AbstractQuery 的散列都应该连接:
def addAbstractionLayerSqlQueries(graph, logger=None):
abstractQueryTable = getAbstractQueries(graph, logger)
sqlqueries = graph.data("MATCH (n:SQLQuery) return n")
if logger is not None:
logger.info("abstracting {} queries".format(len(sqlqueries)))
counter = 1
for iterator in sqlqueries:
query = iterator['n']
if logger is not None:
logger.info("abstracting query {}/{}".format(counter,
len(sqlqueries)))
hash = sqlNormalizer.generate_normalized_query_hash(query['ts'])
if hash not in abstractQueryTable:
abstractQueryNode = al.AbstractQuery(hash)
abstractQueryTable[hash] = abstractQueryNode
graph.push(abstractQueryNode)
rel = Relationship(query, "ABSTRACTSTO", abstractQueryTable[hash])
graph.create(rel)
counter = counter + 1
在开始此过程之前,我会提取所有现有 AbstractQueries 的表(使用哈希作为键),以防止两次创建相同的 AbstractQuery。
但是,当我运行该方法时,我会遇到异常:
TypeError:无法将 AbstractQuery 转换为节点
为什么会这样?我该如何解决?
我之前使用此表示在我的图表中输入了多个SQLQueries:
class SQLQuery(GraphObject):
__primarykey__ = "uuid"
uuid = Property()
projname = Property()
session = Property()
user = Property()
seq = Property()
ts = Property()
sql = Property()
Statement = RelatedTo("SQLStatement")
AbstractsTo = RelatedTo("AbstractQuery")
def __init__(self, projname=None, session=None, user=None,
seq=None, ts=None, sql=None):
self.projname = projname
self.session = session
self.user = user
self.seq = seq
self.ts = ts
self.sql = sql
self.uuid = "{} [{} {}] {}.{}.{}".format(type(self).__name__,
seq, ts, projname,
session, user)
由于我能够使用这种表示来表示和输入节点,我非常惊讶为什么 py2neo 拒绝我的 AbstractQuery 类作为我的 addAbstractionLayerSqlQueries 函数中的节点。
【问题讨论】: