在没有键和值的情况下使用 python 打印 JSON 数据

Question

我目前正在处理一些具有挑战性的 JSON 数据，我需要在我的脚本中的延迟浮动旁边打印设备名称，我可以轻松打印延迟浮动，因为有一个 key:value ，但是设备名称不一样，因此我无法弄清楚如何打印它，尤其是当它为我循环通过以检索数据的每个 API Url 发生变化时

我要打印的数据是"DEVICE123-Et10"

请参阅下面的 JSON 数据，

{
  "notifications": [
    {
      "timestamp": "511513234234",
      "path_elements": [
        "Devices",
        "DEVICE1",
        "versioned-data",
        "connectivityMonitor",
        "status",
        "hostStatus",
        "DEVICE123-Et10",
        "defaultStats"
      ],
      "updates": {
        "httpResponseTime": {
          "key": "httpResponseTime",
          "value": {
            "float": 0
          }
        }
      }
    },
    {
      "timestamp": "15153324243",
      "path_elements": [
        "Devices",
        "DEVICE1",
        "versioned-data",
        "connectivityMonitor",
        "status",
        "hostStatus",
        "DEVICE123-Et10",
        "defaultStats"
      ],
      "updates": {
        "packetLoss": {
          "key": "packetLoss",
          "value": {
            "int": 0
          }
        }
      }
    },
    {
      "timestamp": "151522324234",
      "path_elements": [
        "Devices",
        "DEVICE1",
        "versioned-data",
        "connectivityMonitor",
        "status",
        "hostStatus",
        "DEVICE123-Et10",
        "defaultStats"
      ],
      "updates": {
        "latency": {
          "key": "latency",
          "value": {
            "float": 0.238756565643454
          }
        }
      }
    },
    {
      "timestamp": "158056745645645",
      "path_elements": [
        "Devices",
        "DEVICE1",
        "versioned-data",
        "connectivityMonitor",
        "status",
        "hostStatus",
        "DEVICE123-Et10",
        "defaultStats"
      ],
      "updates": {
        "jitter": {
          "key": "jitter",
          "value": {
            "float": 0.03500000213213
          }
        }
      }
    }
  ]
}

我用来循环浏览我的 URL 列表并获取延迟的当前代码：

     jsonrequest = requests.get(url, cookies=cookies, verify=False).json()
     try:
         print(jsonrequest['notifications'][2]['updates']['latency']['value']['float'])
     except KeyError:
         print(jsonrequest['notifications'][1]['updates']['latency']['value']['float'])```

Answer 1

我继续写了一个脚本来做你想做的事。它循环遍历所有通知，直到找到“延迟”更新。然后它从列表中取出倒数第二个项目，因为它总是倒数第二个。

import json
import requests

data = requests.get(url, cookies=cookies, verify=False).json()
notifications = data["notifications"]
for notification in notifications:
    if notification["updates"].get("latency"):
        latency = notification["updates"]["latency"]["value"]["float"]
        name = notification["path_elements"][-2]
        print(name, latency)