AttributeError：ResultSet 对象没有属性“get_text”。您可能将元素列表视为单个元素答案

【问题标题】：AttributeError: ResultSet object has no attribute 'get_text'. You're probably treating a list of elements like a single elementAttributeError：ResultSet 对象没有属性“get_text”。您可能将元素列表视为单个元素
【发布时间】：2020-03-08 21:56:35
【问题描述】：

我通过 sn-p 用 Bs4 解析得到以下列表：

details = [i.find_all('span', {'class':re.compile('item')}) for i in cars]

[[<span class="item">Red <small>col.</small></span>,
  <span class="item">120 <small>cc.</small></span>,
  <span class="item">Available <small>in four days</small></span>,
  <span class="item"><small class="txt-highlight-red">15 min</small></span>],
 [<span class="item">Blue <small>col.</small></span>,
  <span class="item">200 <small>cc.</small></span>,
  <span class="item">Available <small>in a week</small></span>,
  <span class="item">04 mar <small></small></span>],
 [<span class="item">Green <small>col.</small></span>,
  <span class="item">Available <small>immediately</small></span>,
  <span class="item"><small class="txt-highlight-red">2 hours</small></span>]]

关键是不是每个嵌套列表都具有完全相同的内容或相同的长度，所以我不想简化将文本放在一个单独的列表中。

我试过这段代码：

bobo = []
for detail in details:
    for i in detail:
        bobo.append(i.text)

但正如我所说，它会产生以下输出：

[Red col., 120 cc., Available in four days, 15 min., Blue col., 200 cc., Available in a week, 04 mar , Green col., Available immediately, 2 hours]

而预期的输出是：

[[Red col., 120 cc., Available in four days, 15 min.],
[Blue col., 200 cc., Available in a week, 04 mar ],
[Green col., Available immediately, 2 hours]]

有什么帮助吗？

【问题讨论】：

这样可以吗？ [i.text for i in cars]。您还应该发布源 HTML。

标签： python-3.x beautifulsoup

【解决方案1】：

试试这个

bobo = []
for detail in details:
    result = []
    for i in detail:
        result.append(i.text)
    bobo.append(result)

【讨论】：