如何仅获得具有它的页面的下一页结果？

Question

所以这段代码让我得到了所有的比赛结果，a 队 vs 队和比赛的比分。例如像这样的团队http://www.gosugamers.net/counterstrike/teams/7395-mousesports-cs/matches。但是这段代码只得到第一页的结果，我试图得到每个可用页面的所有结果。问题是一些团队没有下一页按钮，所以当我尝试实现该代码时程序崩溃了。我如何编写代码来获取下一页并继续获取结果，如果团队比赛链接没有下一页就继续？

def all_match_outcomes():
    for match_outcomes in match_history_url():
        rest_server(True)
        page = requests.get(match_outcomes).content
        soup = BeautifulSoup(page, 'html.parser')

        team_name_element = soup.select_one('div.teamNameHolder')
        team_name = team_name_element.find('h1').text.replace('- Team Overview', '')

        for match_outcome in soup.select('table.simple.gamelist.profilelist tr'):
            opp1 = match_outcome.find('span', {'class': 'opp1'}).text
            opp2 = match_outcome.find('span', {'class': 'opp2'}).text

            opp1_score = match_outcome.find('span', {'class': 'hscore'}).text
            opp2_score = match_outcome.find('span', {'class': 'ascore'}).text

            if match_outcome(True):  # If teams have past matches
                print(team_name, '%s %s:%s %s' % (opp1, opp1_score, opp2_score, opp2))

Answer 1

在将游戏分数拉出表格的for 循环之后，您可以获取分页链接。

使用此代码，您可以通过查找当前选定的页面来获取下一页。如果没有超出当前选择的页面，它（当前）将打印“找不到页面”。

paginate = soup.find('div', {'class':'paginator'})

page = paginate.find('a', {'class':'selected'})

next_page = page.find_next_sibling()
if next_page:
    print(next_page.get('href'))
else:
    print("no page found")

编辑

回应评论；这就是我想使用这段代码的方式。然后它将被添加，您可以继续循环。

def all_match_outcomes():
    for match_outcomes in match_history_url():
        rest_server(True)
        page = requests.get(match_outcomes).content
        soup = BeautifulSoup(page, 'html.parser')

        team_name_element = soup.select_one('div.teamNameHolder')
        team_name = team_name_element.find('h1').text.replace('- Team Overview', '')

        for match_outcome in soup.select('table.simple.gamelist.profilelist tr'):
            opp1 = match_outcome.find('span', {'class': 'opp1'}).text
            opp2 = match_outcome.find('span', {'class': 'opp2'}).text

            opp1_score = match_outcome.find('span', {'class': 'hscore'}).text
            opp2_score = match_outcome.find('span', {'class': 'ascore'}).text

            if match_outcome(True):  # If teams have past matches
                print(team_name, '%s %s:%s %s' % (opp1, opp1_score, opp2_score, opp2))
        # get the next page if there is one here
       page = paginate.find('a', {'class':'selected'})
       if page:
           next_page = page.find_next_sibling()
           if next_page:
               print(next_page.get('href'))
               # just append this to a list or add it to whatever you use to 
               # track the next url to crawl
               next_url = next_page.get('href')