【发布时间】：2020-06-20 23:52:15
【问题描述】：
从终端命令response.status 返回200。
从myfile.py 命令requests.get(next_page, headers=headers) 返回<Response [403]>。
我希望从文件中获得200。有什么问题？
myfile.py:
import lxml.html as parser
import requests
headers = {'User-Agent': '"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/83.0.4103.106 Safari/537.36"'}
start_urls = [
#"https://www.vivareal.com.br/aluguel/?__vt=vt:b#banheiros=2&preco-ate=2500&preco-desde=1000&quartos=2"
"https://www.zapimoveis.com.br/aluguel/apartamentos/pe+recife/2-quartos/?__zt=ldt%3Ab&onde=,Pernambuco,Recife,,,,BR%3EPernambuco%3ENULL%3ERecife,-8.0522404,-34.9286096&banheiros=2&quartos=2&transacao=Aluguel&vagas=1&precoMaximo=2500&precoMinimo=1000&tipoUnidade=Residencial,Apartamento&tipo=Im%C3%B3ve^X^X^X^XsdsDSl%20usado&pagina=1"
]
next_page = start_urls[0]
print(next_page)
r = requests.get(next_page, headers=headers)
print(r)
h = parser.fromstring(r.text)
address = h.xpath('//p[contains(@class,"address")]/text()')
print(address)
【问题讨论】：
标签： python python-requests python-requests-html postman-pre-request-script