如何在 Laravel 中使用查询构建器来做到这一点？（子查询 WHERE NOT IN）答案

【问题标题】：How do this in Laravel using the Query Builder? (Subquery WHERE NOT IN)如何在 Laravel 中使用查询构建器来做到这一点？（子查询 WHERE NOT IN）
【发布时间】：2021-11-16 16:39:25
【问题描述】：

SELECT DISTINCT
tasks.id,
tasks.category_id,
(CASE WHEN (SELECT task_id FROM completed_user_tasks WHERE user_id = 1 AND task_id = tasks.id) THEN true ELSE false END) AS completed
  FROM tasks
  WHERE tasks.id NOT IN
  (
    SELECT task_id FROM skipped_user_tasks WHERE user_id = 1
    UNION
    SELECT task_id FROM shown_user_tasks WHERE user_id = 1
    UNION
    SELECT task_id FROM current_user_tasks WHERE user_id = 1
  );

此查询仅返回不在表中的任务：skipped_user_tasks、showed_user_tasks 和 current_user_tasks。另外，在选择时添加了“完成”字段：如果任务在完成的用户任务表中，则返回true，否则返回false。

【问题讨论】：

你可能正在寻找 whereNotIn

标签： mysql sql laravel laravel-query-builder

【解决方案1】：

也许你可以试试这个，看看它是否有效，

$check_events = DB::table('tasks')
              ->selectRaw('SELECT DISTINCT tasks.id, tasks.category_id, (CASE WHEN (SELECT task_id FROM completed_user_tasks WHERE user_id = 1 AND task_id = tasks.id) THEN true ELSE false END) AS completed')
              ->whereRaw('tasks.id NOT IN (SELECT task_id FROM skipped_user_tasks WHERE user_id = 1 UNION SELECT task_id FROM shown_user_tasks WHERE user_id = 1 UNIONSELECT task_id FROM current_user_tasks WHERE user_id = 1)')
              ->get();

【讨论】：