使用日期时间作为键的嵌套字典中的 Python 字典 TypeError答案

【问题标题】：Python dictionary TypeError in nested dictionaries using datetime as a key使用日期时间作为键的嵌套字典中的 Python 字典 TypeError
【发布时间】：2021-07-12 11:56:29
【问题描述】：

我正在尝试按日期时间对以下嵌套字典进行排序，以便首先获得最新记录：

result_devices= 
{
    datetime.datetime(2021, 7, 8, 14, 22, 23): {
        0: ["VC", "10.192.41.15", "-", "OK"],
        1: ["tef", "2.113.85.155", "-", "OK"],
        2: ["AP", "192.168.192.181", "24:f2:7f:ce:f2:ca", "OK"],
        3: ["AP", "192.168.192.182", "-", "OK"],
        4: ["AP", "192.168.192.184", "24:f2:7f:cf:74:14", "OK"],
        5: ["AP", "192.168.192.185", "24:f2:7f:cf:73:74", "OK"],        
    },
    datetime.datetime(2021, 7, 11, 14, 17, 3): {
        6: ["VC", "10.192.41.15", "-", "OK"],
        7: ["tef", "2.113.85.155", "-", "OK"],
        8: ["AP", "192.168.192.181", "24:f2:7f:ce:f2:ca", "OK"],
        9: ["AP", "192.168.192.182", "-", "OK"],
        10: ["AP", "192.168.192.184", "24:f2:7f:cf:74:14", "OK"],        
    },
}

首先我尝试做一个简单的排序：

sorted_result_devices = sorted(result_devices, reverse=True)

但它只返回日期时间，而不是完整的嵌套字典：

sorted_result_devices=
[
    datetime.datetime(2021, 7, 11, 14, 17, 3),
    datetime.datetime(2021, 7, 8, 14, 22, 23),
]

然后我尝试使用 lambda 函数：

sorted_result_devices =sorted(result_devices, reverse=True, key= lambda x:x[0])

但它返回了一个 TypeError: TypeError: 'datetime.datetime' object is not subscriptable

¿对像这样的嵌套字典进行排序的正确方法是什么？

提前致谢

【问题讨论】：

标签： python python-3.x sorting dictionary python-datetime

【解决方案1】：

使用result_devices.items() 作为sorted 中的args

sorted_result_devices = sorted(result_devices.items(), reverse=True)

输出

[(datetime.datetime(2021, 7, 11, 14, 17, 3),
  {6: ['VC', '10.192.41.15', '-', 'OK'],
   7: ['tef', '2.113.85.155', '-', 'OK'],
   8: ['AP', '192.168.192.181', '24:f2:7f:ce:f2:ca', 'OK'],
   9: ['AP', '192.168.192.182', '-', 'OK'],
   10: ['AP', '192.168.192.184', '24:f2:7f:cf:74:14', 'OK']}),
 (datetime.datetime(2021, 7, 8, 14, 22, 23),
  {0: ['VC', '10.192.41.15', '-', 'OK'],
   1: ['tef', '2.113.85.155', '-', 'OK'],
   2: ['AP', '192.168.192.181', '24:f2:7f:ce:f2:ca', 'OK'],
   3: ['AP', '192.168.192.182', '-', 'OK'],
   4: ['AP', '192.168.192.184', '24:f2:7f:cf:74:14', 'OK'],
   5: ['AP', '192.168.192.185', '24:f2:7f:cf:73:74', 'OK']})]

【讨论】：