在 Laravel 4 中从 Jquery Ajax Json 中检索值

Question

我正在尝试从在 Laravel 4 中使用 Ajax 和 Json 的 Jquery 插件检索数据

Plugin 部分在 customer.blade.php 视图中：

<script>
var $container = $("#dataTable");
var $console = $("#example1console");

  var data = {{ $content }};
  $("#dataTable").handsontable({
    data: data,
    startRows: 6,
    startCols: 8,
    rowHeaders: true,
    colHeaders: [{{ $title }}]
  });

var handsontable = $container.data('handsontable');

$container.parent().find('button[name=save]').click(function () {
    //alert('we are trying to save');
  $.ajax({
    url: "/",
    data: {"data": 'demo data'}, //handsontable.getData()}, //returns all cells' data
    dataType: 'json',
    type: 'POST',
    success: function (res) { console.log(res); alert(res); }
   /* error: function () {
      $console.text('Save error. POST method is not allowed on GitHub Pages. Run this example on your own server to see the success message.');
    }*/
  });
});
</script>

在 Routes.php 我有：

// here i wanna send json data to plugin and render the view 
Route::get('/', 'CustomerController@getIndex');
// here i wanna retrieve the  json-data from the plugin and save it later in db
Route::post('/', 'CustomerController@postSave');

在控制器中我有：

public function getIndex() {
    //$cust = Customer::get()->toJson();
    //$cust = InformationDB::select('Column_Name')->where('table_name', '7_0 - CRONUS (ai-Patches) AG$Customer')->get()->toJson();

    // Get Columns
    $cust = Customer::select('Name', 'City')->get()->toJson();
    // Get Columns Title
    $getTitle = Customer::select('Name', 'City')->first()->toJson();
    $title = implode(', ',array_keys(json_decode($getTitle, true)));
    $title4js = "'" . str_replace(",", "','", $title) . "'";
    // Render View
    return View::make('customer/customer', array('content' => $cust, 'title' => $title4js));
}

public function postSave() {
    $t = Input::all(); 
    return $t;
}

也许有人知道我做错了什么？

Answer 1

在您的ajax post 请求中，而不是

url: "/",

你必须使用，

url: "/laranav/public/",

laranav 将是您的项目目录。