为另一个 Python 程序创建 UI。如何在 tkinter 中为 Python 3 制作打印标签？

Question

我正在为另一个 python 程序创建一个 UI，它本质上只是为项目创建了一个交互式组件。目标是有一个特定的标签，从按钮运行的 python 程序更新（打印语句）。这是我在我的 UI 中编写的...

---

import tkinter as ttk
import subprocess
import sys
import time
import os
import tkinter.font as font
from tkinter.ttk import *

app = ttk.Tk()

app.geometry("400x400")
app.configure(bg='gray')

photo = ttk.PhotoImage(file=r"C:\Users\ex\ex_button_active.png")
myFont = font.Font(family='Helvetica', size=20, weight='normal')

ttk.Label(app, text='Ex', bg='gray', font=(
    'Verdana', 15)).pack(side=ttk.TOP, pady=10)
app.iconbitmap(r'C:\Users\ex\ex_icon.ico')


def ex_activation():
    global pro
    print("Running program!")
    pro = subprocess.Popen("python programex.py", shell=True)


def ex_stop():
    global pro
    print("Stopping Program... Please Wait!")
    os.kill(pro.pid, 0)


ex_activation_button = ttk.Button(app, bg='black', image=photo, width=120, height=120, command=ex_activation)

ex_stop_button = ttk.Button(app, bg='Gray', text='Stop Program', width=12, command=ex_stop, height=3)

ex_stop_button['font'] = myFont

app.title("Ex")
ex_activation_button.pack(side=ttk.TOP)
ex_stop_button.pack(side=ttk.LEFT)

# app.mainloop()
while True:
    try:
        app.update()
        app.update_idletasks()
    except KeyboardInterrupt:
        pass

---

如果有人知道如何在我的代码中实现This StackOverflow Post，我将非常感谢您的帮助和支持。

编辑 acw1668 这些是我运行的一些测试，在 Pycharm 运行窗口而不是 UI 中得到了一些奇怪的数字。

Running program!
3528
Stopping Program 3528 ... Please Wait!
monitor done
Running program!
144
Stopping Program 144 ... Please Wait!
monitor done
Running program!
14008
Stopping Program 14008 ... Please Wait!
monitor done
Running program!
21748
Stopping Program 21748 ... Please Wait!
monitor done

Answer 1

我使用了您的代码的简化版本。要在 tkinter 应用程序中获取打印状态，我想到的最简单的方法是使用第三个文件：在我的例子中，log.txt。

daemon.py 将log() 一些输出（自定义函数）到文本文件而不是打印它。在 tkinter 主循环中，应用程序将不断检查对该文件的更改。

请注意，使用 file.readline()，我只阅读一行，因为 tkinter Labels 更喜欢这样。如果您计划使用更多行，则可以将标签更改为文本区域。

无论如何：这是代码。我希望它能在你的项目中工作！

# FILE 1: daemon.py

from time import sleep
from sys import exit

def log(s): # This will be the equivalent to the print function
    with open("log.txt", "w") as fileout:
        fileout.write(s)

x = 0
while True:
    try:
        log("seconds elapsed: " + str(x))
        x+=1
        sleep(1)
    except KeyboardInterrupt:
        log("Stopping with x =" + str(x))
        exit()

# FILE 2: log.txt

# You can leave this file empty, but you must create a file named 'log.txt'.

# FILE 3: mainapp.py

import tkinter as tk
import subprocess
import os

def ex_activation():
    print("Running")
    global pro
    pro = subprocess.Popen("python daemon.py", shell=True)

def ex_stop():
    print("Stopped") # I just dont know why, but this print can't be removed.
    global pro
    os.kill(pro.pid, 0)

app = tk.Tk()

ex_activation_button = tk.Button(app, text="run", command=ex_activation)
ex_stop_button = tk.Button(app, text="stop", command=ex_stop)
lab = tk.Label(app, text="If you see this, an error occurred")

with open("log.txt", "w+") as fileinout:
    fileinout.write("Click run to start the execution!")
    lab.config(text=fileinout.readline())

ex_activation_button.pack()
ex_stop_button.pack()
lab.pack()

# app mainloop
while True:
    try:
        app.update()
        app.update_idletasks()
        with open( "log.txt", "r" ) as filein:
            lab.config(text=filein.readline())
    except KeyboardInterrupt:
        pass