替换值并重建json数据python

Question

我有一个场景，我有以下 json 数据

 data = {
      "app": [
        {
          "ida": 10,
          "configur": {
            "config": [
              {
                "active": "true",
                "tol": "id"
              }
            ]
          }
        },
        {
          "ida": 11,
          "configur": {
            "config": [
              {
                "active": "true",
                "tol": "id"
              }
            ]
          }
        },    {
          "ida": 11,
          "configur": {
            "config": [
              {
                "active": "true",
                "tol": "id"
              }
            ]
          }
        }
      ]
    }

这里我想将每个元素中的tol 值替换为ida

这是我的代码：

  data3 = []
  for cmpkey2 in data['app']:
        spcmpg = cmpkey2['configur']['config']
        tempev = cmpkey2['ida']
        for key34 in spcmpg:
            key34['tol'] = tempev
        data3.append({ "ida": tempev, "config": spcmpg})

这里的新字典 data3 没有用 ida 值替换 tol 值，我在哪里做错了？ 任何帮助都会很棒！

Answer 1

如果是字典，您不能更改键的名称，您可以删除该键或创建一个新键

我找到了解决您问题的方法，

data = {
      "app": [
        {
          "ida": 10,
          "configur": {
            "config": [
              {
                "active": "true",
                "tol": "id"
              }
            ]
          }
        },
        {
          "ida": 11,
          "configur": {
            "config": [
              {
                "active": "true",
                "tol": "id"
              }
            ]
          }
        },    {
          "ida": 11,
          "configur": {
            "config": [
              {
                "active": "true",
                "tol": "id"
              }
            ]
          }
        }
      ]
    }

val=''
data3 = []
for cmpkey2 in data['app']:
    spcmpg = cmpkey2['configur']['config']

    tempev = cmpkey2['ida']
    for key34 in spcmpg:

        val=cmpkey2['ida']
        key34['tol']=val


    data3.append({ "ida": tempev, "config": spcmpg})
print(data3)

在此代码中，它创建一个新键并将 tol 的值分配给该键，然后删除 tol 键

输出：

[{'ida': 10, 'config': [{'active': 'true', 'tol': 10}]}, {'ida': 11, 'config': [{'active': 'true', 'tol': 11}]}, {'ida': 11, 'config': [{'active': 'true', 'tol': 11}]}]

Answer 2

你能试试下面的代码，看看你是否期望你的输出是这样的

data3 = []

for item in data['app']:
    new_dict = {}
    config_list = []
    ida_value = item['ida']
    config_list = item['configur']['config']
    config_list[0]['tol'] = ida_value
    new_dict['ida'] = ida_value
    new_dict['config'] = config_list
    data3.append(new_dict)
print(data3)

输出

[
   {
      "ida":10,
      "config":[
         {
            "active":"true",
            "tol":10
         }
      ]
   },
   {
      "ida":11,
      "config":[
         {
            "active":"true",
            "tol":11
         }
      ]
   },
   {
      "ida":11,
      "config":[
         {
            "active":"true",
            "tol":11
         }
      ]
   }
]